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zvonat [6]
3 years ago
8

Ben day outside his school in Cambridge and made a note of the colour of the first 100 cars that passed. 27 of the cars were red

. In Britain there are around 35 million cars on the road. Use Ben’s findings to give an estimate of how many cars on the road are red.
Mathematics
1 answer:
Vika [28.1K]3 years ago
5 0

Answer:

9450000 red cars

Step-by-step explanation:

Out of 100 cars that passed, 27 of them where red.

The probability of red car to pass = 27/100

Probability of red car to pass = 0.27.

Now we are given a new value.

The value is 35 million cars.

Which is equal to 35000000.

We are asked to estimate the number of cars that will be red from Ben previous calculations.

The estimate = probability of red cars passing* number of cars in total

The estimate = 0.27 * 35000000

The estimate = 9450000

So we expect 9450000 red cars to pass

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Think of the two pieces together as a single cone of height 19, and its volume.
Then think of only the upper piece as a cone, and find its volume.
The volume of the frustum is the total volume minus the volume of the upper piece.

The volume of a cone is:

V = \dfrac{1}{3} \pi r^2 h

Total volume:

V_t = \dfrac{1}{3} \times \pi \times 7.5^2 \times 19

Volume of upper cone:

V_u = \dfrac{1}{3} \times \pi \times 3.5^2 \times 8

Volume of frustum:

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4 years ago
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Refer to the previous exercise. The researchers wanted a sufficiently large sample to be able to estimate the probability of pre
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Answer:

<em>The large  sample n = 117.07</em>

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given that the estimate error (M.E) = 0.08

The proportion (p) = 0.75

q =1-p = 1- 0.75 =0.25

Level of significance = 0.05

Z₀.₀₅ = 1.96≅ 2

<u><em>Step(ii):-</em></u>

The Marginal error is determined by

M.E = \frac{Z_{0.05} \sqrt{p(1-p)}  }{\sqrt{n} }

0.08 = \frac{2 X \sqrt{0.75(1-0.75)}  }{\sqrt{n} }

Cross multiplication , we get

\sqrt{n}  = \frac{2 X \sqrt{0.75(1-0.75)}  }{0.08 }

√n = \frac{2 X0.4330}{0.08} = 10.825

squaring on both sides , we get

n = 117.07

<u><em>Final answer:-</em></u>

<em>The large  sample n = 117.07</em>

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Make y the subject of formula

y= 1340÷15

y=89.33cows

Therefore,the number of cows on the farm if farmer gets 1340litres of milk would be 89cows.

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