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leonid [27]
3 years ago
14

0.33+0.09= m mmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmmm

Mathematics
1 answer:
Helen [10]3 years ago
8 0

Answer:

0.42

Step-by-step explanation:

Add 9 to 3 to get 12, divide 12 by 100 and add it to 0.3 to get your answer.

You might be interested in
Evaluate using properties of arithmetic operations. 12∙121∙13÷(26∙11)∙7÷11
Anika [276]

Answer:

0.1978

Step-by-step explanation:

According to the rule of BODMAS (or FEDMAS), let us do the bracket first.

26·11 = 286

Now, do the multiplication from the left.

12·121·3 = 4356

286·7 = 2002

Now, do the division from the left.

\frac{\frac{4356}{2002} }{11}

=\frac{4356}{2002(11)}

=\frac{396}{2002}

= 0.1978



8 0
3 years ago
Wich one is bigger 3/3 or 7/8
MrRissso [65]
3/3=1 and 7/8 is < 1 so 3/3 is bigger
4 0
3 years ago
The mean volume for a bottle of cologne is 4 ounces and the standard deviation is 0.22 ounces. A random sample of 121 bottles is
adelina 88 [10]

Answer:

The standard error of the mean is 0.02

Step-by-step explanation:

Here, we want to calculate the standard error of the mean.

Mathematically;

standard error of mean = SD/ √n

where SD is the standard deviation and n is the number of samples

From the question, SD = 0.22 and n = 121

Inserting this into the equation

Standard error of the mean = 0.22/√121

= 0.22/11 = 0.02

6 0
3 years ago
A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon
fiasKO [112]

Answer:

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

A store randomly samples 603 shoppers over the course of a year and finds that 142 of them made their visit because of a coupon they'd received in the mail.

This means that n = 603, \pi = \frac{142}{603} = 0.2355

95% confidence level

So \alpha = 0.05, z is the value of Z that has a p-value of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694

The 95% confidence interval for the fraction of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694).

8 0
2 years ago
What is the value of the expression “two less than six times the difference of a number and five" when n =
Vinvika [58]
It’s 16 because Ik I did it before so do y worry
8 0
2 years ago
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