Let events
A=Nathan has allergy
~A=Nathan does not have allergy
T=Nathan tests positive
~T=Nathan does not test positive
We are given
P(A)=0.75 [ probability that Nathan is allergic ]
P(T|A)=0.98 [probability of testing positive given Nathan is allergic to Penicillin]
We want to calculate probability that Nathan is allergic AND tests positive
P(T n A)
From definition of conditional probability,
P(T|A)=P(T n A)/P(A)
substitute known values,
0.98 = P(T n A) / 0.75
solving for P(T n A)
P(T n A) = 0.75*0.98 = 0.735
Hope this helps!!
The answer would be 8! This is because there were already five and then Jason got in, so six, and then two friends got in as well, so six plus two is eight!
Answer:
7,-5,-11
Step-by-step explanation:
-3(-4)-5=7
-3(0)-5=-5
-3(2)-5=-11
500,000 + 8,000 = 508,000
The answer would be
<span>B)
A' (-8, 5)
B' (-8, 8)
C' (-5, 7)
D' (-4.5, 5)</span>
