L = 5W - 10
5W = L + 10
W = 1/5(L + 10)
Area = L x W
240 = L(1/5(L + 10)
L^2 + 10L = 240(5) = 1200
L^2 + 10L - 1,200 = 0
Answer: 1 and one fourths because 1/4 times 5 is 1 1/4
Step-by-step explanation:
Answer:
6. 10^3 ten to the third power
7. 10^5 ten to the fifth power
8. not sure
10. 60
19. 20
11-13: not sure
and i can't understand the rest
Step-by-step explanation:
Answer:
-22x-11
Step-by-step explanation:
Your welcome! :)
We have been given the expression to be 
Since we need to find the tangent at a point, we will have to find the derivative of
as the slope of the tangent at a given point on the curve is always equal to value of the derivative at that point.
Thus, we have to find 
We will use the product rule of derivatives to find 
Thus,
(using the product rule which states that
)
Taking the common factors out we get:


Thus,
at
is given by:
=Slope of the tangent of y at x=4=
Thus, 
Now, the equation of the tangent line which passes through
and has slope m is given by:

Thus, the equation of the tangent line which passes through
and has the slope 185 is
Which can be simplified to 
Thus, 
This is the required equation of the tangent.