Answer:
I just finished the test with an 82. Here are the answers
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The given inequality holds for the open interval (2.97,3.03)
It is given that
f(x)=6x+7
cL=25
c=3
ε=0.18
We have,
|f(x)−L| = |6x+7−25|
= |6x−18|
= |6(x−3)|
= 6|x−3|
Now,
6|x−3| <0.18 then |x−3|<0.03 ----->−0.03<x-3<0.03---->2.97<x<3.03
the given inequality holds for the open interval (2.97,3.03)
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Although part of your question is missing, you might be referring to this full question: For the given function f(x) and values of L,c, and ϵ0, find the largest open interval about c on which the inequality |f(x)−L|<ϵ holds. Then determine the largest value for δ>0 such that 0<|x−c|<δ→|f(x)−|<ϵ.
f(x)=6x+7,L=25,c=3,ϵ=0.18
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Answer:
The factors are 9, y, 2, 2, y and 2.
Step-by-step explanation:
when you combine a number with another number, then that means you need to multiply. The 2 numbers that are multiplied are the factors.
Answer:
Step-by-step explanation:
if you see a person that sends you a sketchy link dont click it is an ip grabber.
Complementary angles, when added, = 90 degrees
S + L = 90
S = L - 5
L - 5 + L = 90
2L - 5 = 90
2L = 90 + 5
2L = 95
L = 95/2
L = 47.5 ...larger angle
S = L - 5
S = 47.5 - 5
S = 42.5 <== smaller angle
