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harkovskaia [24]
4 years ago
14

Which expression is equivalent to 8x-2y+x+x=

Mathematics
1 answer:
sammy [17]4 years ago
6 0
<span>8x-2y+x+x=10x-2y

P.s. I just evaluated the expression </span><span>8x-2y+x+x
</span>
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HELP DUE IN 5 MINUTES​
Daniel [21]

\huge \mathfrak \blue{Solution \:  - }

The formula for area of triangle is -

\frac{1}{2}   \times base \times height

________________________________

So, the area of first triangle =

\frac{1}{2}  \times base \:  \times height

\frac{1}{2}  \times 4  \times 3

=  \pink{6  \: units}

________________________________

Area of second triangle =

\frac{1}{2 }  \times base \times height

\frac{1}{2}  \times 4 \times 6

=  \pink {12 \:  units}

________________________________

Area of second triangle - Area of first triangle

= 12 - 6

= 6

\sf \underline\purple{The \: area \: increases \: by \: 6 \: square \: units.}

3 0
3 years ago
Read 2 more answers
Use two 2-Column proofs to show that either diagonal of a rectangle will create two congruent triangles?
tangare [24]
<span>Given: Rectangle ABCD 
Prove: ∆ABD≅∆CBD 
Solution:
                      
           <span> Statement                                       Reason 
</span>
  ABCD is a parallelogram          Rectangles are parallelograms since the                                                          definition of a parallelogram is a quadrilateral                                                    with two pairs of parallel sides.

Segment AD = Segment BC       The opposite sides of a parallelogram are     Segment AB = Segment CD       congruent. This is a theorem about the                                                              parallelograms.

</span>∆ABD≅∆CBD                             SSS postulate: three sides of ΔABD is                                                           equal to the three sides of ∆CBD<span>


</span><span>Given: Rectangle ABCD 
Prove: ∆ABC≅∆ADC
</span>Solution:
                      
           <span> Statement                                       Reason 
</span>
    Angle A and Angle C                 Definition of a rectangle: A quadrilateral     
        are right angles                      with four right angles.

        Angle A = Angle C                 Since both are right angles, they are                                                                  congruent

Segment AB = Segment DC       The opposite sides of a parallelogram are     Segment AD = Segment BC       congruent. This is a theorem about the                                                              parallelograms.

            ∆ABC≅∆ADC                   SAS postulate: two sides and included                                                         angle of ΔABC is congruent to the two                                                         sides and included angle of ∆CBD
6 0
3 years ago
Please help i really need it
Dennis_Churaev [7]

Answer:

6/63

Step-by-step explanation:

To find the probability in fraction form you must first add all the evidence together and then use that number as the denominator

7 0
2 years ago
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You roll a six sided die how likely is it that you roll a number greater than or equal to 1
Grace [21]

Answer:

6/6

Step-by-step explanation:

3 0
3 years ago
Find x and y 30 points
Vika [28.1K]

Since the two triangles are similar

\frac{5 + x}{5}  =  \frac{7 + y}{7}  =  \frac{10}{8}  \\ \implies \frac{5 + x}{5}  =  \frac{10}{8}  \\ \implies x =  \frac{50}{8}  - 5 =  \frac{50 - 40}{8}  =  \frac{10}{8}   =  \frac{5}{4} \\  \therefore x =   \frac{5}{4}

Also,

\\ \frac{7 + y}{7}  =  \frac{10}{8}  \\ \implies y =  \frac{70}{8}  - 7 =  \frac{70 - 56}{8}  \\  \therefore y =   \frac{14}{8}  =  \frac{7}{4}

7 0
3 years ago
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