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blagie [28]
2 years ago
13

What is the simplified form of √ 144x36?

Mathematics
1 answer:
yKpoI14uk [10]2 years ago
5 0

Answer:

12x^18

Step-by-step explanation:

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Please help with this
Likurg_2 [28]
Idk know the answer sorry
3 0
3 years ago
3x+2(x-5)=25 show your work
Zanzabum

Answer:

x = 7

Step-by-step explanation:

Expand 3x+2(x-5)=25 which looks like

3x+2x-10=25

Add similar elements: ( 3x+2x = 5x)

5x-10=25

Add 10 to both sides

5x-10+10 = 25 + 10

Simplfy

5x = 35

Divide both sides by 5

5x ÷ 5 = 35 ÷ 5  

Simplfy:

x = 7

have a wonderful day

8 0
3 years ago
a triangle with vertices at A (-1,1), B(-2,1) C(-1,4) is translated. the image of vertex A has coordinate at (3,-1) determine th
Drupady [299]
For this case we have the following vertices:
 A (-1,1) --------> A '(3, -1)
 B (-2.1)
 C (-1,4)
 We note that the translation rule is:
 (x, y) -----------> (x + 4, y-2)
 Applying the translacion rule we have:
 B (-2, 1) -----------> (-2 + 4, 1-2) ------> B '(2, -1)
 C (-1, 4) -----------> (-1 + 4, 4-2) ------> C '(3, 2)
 Answer:
 
The image of vertex B or the image of Vertex C are:
 
B '(2, -1)
 
C '(3, 2)
7 0
4 years ago
Find the value of x. A)21 B)27 C)31 D)34
wariber [46]

Answer:

C

Step-by-step explanation:

BC its backwards den the 1+3x

8 0
3 years ago
Read 2 more answers
A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters
In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

\Rightarrow y=\sqrt{x^2+100}

Differentiating with respect to t

\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}

\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}

Since the car driving towards the intersection at 13 m/s.

so,\frac{dx}{dt}=-13

\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)

Now

\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)

               =\frac{24\times (-13)}{\sqrt{676}}

               =\frac{24\times (-13)}{26}

               = -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0
3 years ago
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