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3 years ago

A variable must have its type declared but it is not required to be initialized prior to first use.

Computers and Technology

1 answer:

chubhunter [2.5K]3 years ago

3 0

Answer:

The correct answer for the given question is option(A).

Explanation:

variable are the storage area which value is change during the execution of program

to declared any variable we use the following syntax

datatype variablename ;

for example

int a1;// declared variable a1 of type integer

a1=90; // initialized variable a1

To declared any variable it does not mendatory to intialized that vaiable at that time but when we using any variable it mendatory to intialized that variable.

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Complete the do-while loop to output every number form 0 to countLimit using printVal. Assume the user will only input a positiv

elena-s [515]

Answer:

PART ONE

import java.util.Scanner;
public class CountToLimit {
public static void main(String[] args) {
Scanner scnr = new Scanner(System.in);
int countLimit = 0;
int printVal = 0;
// Get user input
System.out.println("Enter Count Limit");
countLimit = scnr.nextInt();
do {
System.out.print(printVal + " ");
printVal = printVal + 1;
} while ( printVal<=countLimit );
System.out.println("");
return;
}
}

PART TWO

import java.util.Scanner;
public class NumberPrompt {
public static void main (String [] args) {
Scanner scnr = new Scanner(System.in);
System.out.print("Your number < 100: ");
int userInput = scnr.nextInt();
do {
System.out.print("Your number < 100: ");
userInput = scnr.nextInt();
}while (userInput>=100);
System.out.println("Your number < 100 is: " + userInput);
return;
}
}

Explanation:

In Part one of the question, The condition for the do...while loop had to be stated this is stated on line 14

In part 2, A do....while loop that will repeatedly prompt user to enter a number less than 100 is created. from line 7 to line 10

7 0

3 years ago

Which is an effect of short-term environmental changes?

allochka39001 [22]

Adaptation or death

.

4 0

3 years ago

Demote the "Arrive and leave at the same time each day." List item, and then promote the "Respect" list item.

garri49 [273]

Answer:

Dear

<h3>You should wear something professional. A tie, suit, classy dress, heels. You are more likely to be hired if you make it look like you take pride in your appearance. Also, depending on what kind of job you are applying for, the outfits can vary as well.</h3>

Explanation:

Black is too formal for interviews, and earth tones are too casual. Two-button suits are the professional standard.

7 0

4 years ago

Find the root using bisection method with initials 1 and 2 for function 0.005(e^(2x))cos(x) in matlab and error 1e-10?

frutty [35]

Answer:

The root is:

$c=1.5708$

Explanation:

Use this script in Matlab:

-------------------------------------------------------------------------------------

function [c, err, yc] = bisect (f, a, b, delta)

% f the function introduce as n anonymous function

% - a y b are the initial and the final value respectively

% - delta is the tolerance or error.

% - c is the root

% - yc = f(c)

% - err is the stimated error for c

ya = feval(f, a);

yb = feval(f, b);

if ya*yb > 0, return, end

max1 = 1 + round((log(b-a) - log(delta)) / log(2));

for k = 1:max1

c = (a + b) / 2;

yc = feval(f, c);

if yc == 0

a = c;

b = c;

elseif yb*yc > 0

b = c;

yb = yc;

else

a = c;

ya = yc;

end

if b-a < delta, break, end

end

c = (a + b) / 2;

err = abs(b - a);

yc = feval(f, c);

-------------------------------------------------------------------------------------

Enter the function in matlab like this:

f= @(x) 0.005*(exp(2*x)*cos(x))

You should get this result:

f =

function_handle with value:

@(x)0.005*(exp(2*x)*cos(x))

Now run the code like this:

[c, err, yc] = bisect (f, 1, 2, 1e-10)

You should get this result:

c =

1.5708

err =

5.8208e-11

yc =

-3.0708e-12

In addition, you can use the plot function to verify your results:

fplot(f,[1,2])

grid on

5 0

3 years ago

What are the 5 characteristics of flowchart<br>

olchik [2.2K]

Answer:

Here's ur answer

Explanation:

(i) Should consist of standardized and acceptable symbols. (ii) The symbols should be correctly used according to flowcharts rules. (iii) Should have short, clear and readable statements written inside the symbols. (iv) It must have clear one starting point and one ending point.

3 0

3 years ago