Question

Ericka decided to compare her observation to the average annual trend, which shows the water rising 1.8 mm/year. Remember, she used 6.2 years as her time period. Explain how she would calculate the difference between how much water levels rose on average and how much the water level fell in the part of the river she observed.

Answer 1

Answer:

She would multiply the rate by the years to find the average rise in water levels, or 1.8 times 6.2 = 11.16. To find the difference between the water levels, she would subtract -13.64 from 11.16.

Step-by-step explanation:

Answer 2

Answer with explanation:

Presume that, initial water level to be, 0 mm, at a time t=0.

And water level is rising at the rate of $1.8 \frac{\text{mm}}{\text{year}}$.

 After 6.2 years level of water will be =1.8 × 6.2

                                                           =11.16 mm

→Averge, that is increase in water level after 6.2 years is given by

                     $=\frac{W_{2}-W_{1}}{t_{2}-t_{1}}\\\\=\frac{11.16-0}{6.2-0}\\\\=\frac{11.16}{6.2}\\\\=1.8 \frac{\text{mm}}{\text{year}}$

→→Rate of Depreciating of water level is given by = Negative of Increase of water level=$-1.8 \frac{\text{mm}}{\text{year}}$