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3 years ago

Cost of a comic book $3.95 markup 20%

2 answers:

5 0

If you mean the price is now 120% of the original, $<span>4.74 (3.95 * 0.8) is the new price.

If you mean the price is now 80% of the original, $3.16 (3.95 * 1.2) is the new price.</span>

Galina-37 [17]3 years ago

3 0

3.95x20=79/100=0.79

3.95
+ 0.79
_____
4.74 is the new price

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Jordan is running 5 miles for cross-country practice (track). She ran the first 2 miles in 12.5 minutes. How long will it take h

pochemuha

Answer:

31.25 minutes

Step-by-step explanation:

12.5 minutes divided by 2 (miles) = 1 mile per 6.25 minutes

6.25 x 5 = 31.25

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3 years ago

A box contains twenty cards numbered 1 through 20. One card is to be randomly drawn from the box.

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C.7/20
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3 years ago

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En una olimpiada matemática, cada estudiante recibe un punto por cada pregunta acertada. En la siguiente tabla de frecuencias se

Leviafan [203]

La tabla relacionada con la pregunta se puede encontrar en la imagen adjunta a continuación:

Responder:

70%

Explicación paso a paso:

probabilidad de seleccionar aleatoriamente a un participante que haya obtenido entre 71 y 85 puntos:

Probabilidad = resultado requerido / Total de resultados posibles

Resultados posibles totales = Sumando la frecuencia para obtener el número total de estudiantes = (9 + 12 + 12 + 18 + 9) = 60 estudiantes

Resultado requerido:

Clase :

(71 - 75) = frecuencia = 12

(76 - 80) = frecuencia = 12

(81 - 85) = frecuencia = 18

Total = (12 + 12 + 18) = 42 = resultado requerido

Por tanto, P = 42/60 = 0,7 = (0,7 * 100%) = 70%

4 0

2 years ago

If y is a differentiable function of x, then the slope of the tangent to the curve xy-2y 4y^2=6 at the point where y=1 is

Molodets [167]

7 0

3 years ago

I need help with this question

Novay_Z [31]

Answer:

$\frac{\sqrt{3} - 1}{2\sqrt{2}}$

$\frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

$- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$

Step-by-step explanation:

Given $\frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6}$

(A) $sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4} + \frac{\pi}{6})$

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2}$

$$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}$

(B) Cos(A + B) = CosAcosB - SinASinB

$cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}})$

$\implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2}$

$\implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6})$

$$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}$

From the above obtained values this can be calculated and the value is $- \frac{\sqrt{3} - 1}{\sqrt{3} + 1}$ .

3 0

3 years ago