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swat32
3 years ago
9

Cost of a comic book $3.95 markup 20%

Mathematics
2 answers:
Sergeu [11.5K]3 years ago
5 0
If you mean the price is now 120% of the original, $<span>4.74 (3.95 * 0.8) is the new price.

If you mean the price is now 80% of the original, $3.16 (3.95 * 1.2) is the new price.</span>
Galina-37 [17]3 years ago
3 0
3.95x20=79/100=0.79

3.95
+ 0.79
_____
4.74 is the new price
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Jordan is running 5 miles for cross-country practice (track). She ran the first 2 miles in 12.5 minutes. How long will it take h
pochemuha

Answer:

31.25 minutes

Step-by-step explanation:

12.5 minutes divided by 2 (miles) = 1 mile per 6.25 minutes

6.25 x 5 = 31.25

6 0
3 years ago
A box contains twenty cards numbered 1 through 20. One card is to be randomly drawn from the box.
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C.7/20              
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3 0
3 years ago
Read 2 more answers
En una olimpiada matemática, cada estudiante recibe un punto por cada pregunta acertada. En la siguiente tabla de frecuencias se
Leviafan [203]

La tabla relacionada con la pregunta se puede encontrar en la imagen adjunta a continuación:

Responder:

70%

Explicación paso a paso:

probabilidad de seleccionar aleatoriamente a un participante que haya obtenido entre 71 y 85 puntos:

Probabilidad = resultado requerido / Total de resultados posibles

Resultados posibles totales = Sumando la frecuencia para obtener el número total de estudiantes = (9 + 12 + 12 + 18 + 9) = 60 estudiantes

Resultado requerido:

Clase :

(71 - 75) = frecuencia = 12

(76 - 80) = frecuencia = 12

(81 - 85) = frecuencia = 18

Total = (12 + 12 + 18) = 42 = resultado requerido

Por tanto, P = 42/60 = 0,7 = (0,7 * 100%) = 70%

4 0
2 years ago
If y is a differentiable function of x, then the slope of the tangent to the curve xy-2y 4y^2=6 at the point where y=1 is
Molodets [167]
<span>x(1^2)-2(1)+4(1^3)=6
x - 2 + 4 = 6
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7 0
3 years ago
I need help with this question
Novay_Z [31]

Answer:

$ \frac{\sqrt{3} - 1}{2\sqrt{2}} $

$ \frac{-(\sqrt{3} + 1)}{2\sqrt{2}} $

$ - \frac{\sqrt{3} - 1}{\sqrt{3} + 1} $

Step-by-step explanation:

Given $ \frac{11 \pi}{12} = \frac{3 \pi}{4} + \frac{\pi}{6} $

(A) $ sin(\frac{11\pi}{12}) = sin (\frac{3 \pi}{4}  + \frac{\pi}{6}) $

We know that Sin(A + B) = SinA cosB + cosAsinB

Substituting in the above formula we get:

$ sin (\frac{3\pi}{4} + \frac{\pi}{6}) = \frac{1}{\sqrt{2}} . \frac{\sqrt{3}}{2} + \frac{-1}{\sqrt{2}}. \frac{1}{2} $

$ \implies \frac{1}{\sqrt{2}} (\frac{\sqrt{3} - 1}{2}) = \frac{\sqrt{3} - 1}{2\sqrt{2}}

(B) Cos(A + B) = CosAcosB - SinASinB

$ cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}}) $

$ \implies \frac{-1}{\sqrt{2}}. \frac{\sqrt{3}}{2} - \frac{1}{\sqrt{2}} . \frac{1}{2} $

$ \implies cos(\frac{11\pi}{12}) = cos(\frac{3\pi}{4} + \frac{\pi}{6}) $

$ = \frac{-(\sqrt{3} + 1)}{2\sqrt{2}}

(C) Tan(A + B) = $ \frac{Sin(A +B)}{Cos(A + B)} $

From the above obtained values this can be calculated and the value is $ - \frac{\sqrt{3} - 1}{\sqrt{3} + 1} $.

3 0
3 years ago
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