Question

Graph the function represented in the table on the coordinate plane.

Answer 1

I hope this helps you

Answer 2

Answer:

$2x-y+1=0$

Step-by-step explanation:

The given points are,

$(-2,-3),(-1,-1),(0,1),(1,3),(2,5)$

The difference in x coordinates is 1 and the difference in y coordinates is also 1. As change in both x and y are same and constant, so graph will be a straight line.

Plotting the points on the Cartesian coordinates, we get a straight line.

Applying two point formula, taking (-2,-3), (-1,-1), we get

$\Rightarrow \dfrac{y-y_1}{y_2-y_1}=\dfrac{x-x_1}{x_2-x_1}$

$\Rightarrow \dfrac{y+3}{-1+3}=\dfrac{x+2}{-1+2}$

$\Rightarrow \dfrac{y+3}{2}=\dfrac{x+2}{1}$

$\Rightarrow y+3=2(x+2)$

$\Rightarrow y+3=2x+4$

$\Rightarrow 2x-y+1=0$