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Vlad1618 [11]
3 years ago
5

What is the measure of an angle whose degree is five times its compliment?​

Mathematics
1 answer:
Leokris [45]3 years ago
8 0

Answer: 150 Degrees

Step-by-step explanation:

150 degrees

since the ratio is 5: 1, certainly there are 6 parts,

so, one part equals, 30, which 180/6,

hence the complement angle which is five times more will be 5*30 = 150.

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Please help! It will be appreciated!
AysviL [449]
It’s d, looks like you got it already! With ratios, just pay attention to not only the numbers but order of the words as well, so you can be sure the ratio follows the problem.
8 0
3 years ago
Read 2 more answers
Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br
Lina20 [59]

Answer:

The differential equation for the amount of salt A(t) in the tank at a time  t > 0 is \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

Step-by-step explanation:

We are given that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

The concentration of the solution entering is 4 lb/gal.

Firstly, as we know that the rate of change in the amount of salt with respect to time is given by;

\frac{dA}{dt}= \text{R}_i_n - \text{R}_o_u_t

where, \text{R}_i_n = concentration of salt in the inflow \times input rate of brine solution

and \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

So, \text{R}_i_n = 4 lb/gal \times 3 gal/min = 12 lb/gal

Now, the rate of accumulation = Rate of input of solution - Rate of output of solution

                                                = 3 gal/min - 2 gal/min

                                                = 1 gal/min.

It is stated that a large mixing tank initially holds 500 gallons of water, so after t minutes it will hold (500 + t) gallons in the tank.

So, \text{R}_o_u_t = concentration of salt in the outflow \times outflow rate of brine solution

             = \frac{A(t)}{500+t} \text{ lb/gal } \times 2 \text{ gal/min} = \frac{2A(t)}{500+t} \text{ lb/min }

Now, the differential equation for the amount of salt A(t) in the tank at a time  t > 0 is given by;

= \frac{dA}{dt}=12\text{ lb/min } - \frac{2A(t)}{500+t} \text{ lb/min }

or \frac{dA}{dt}=12 - \frac{2A(t)}{500+t}.

4 0
3 years ago
Solve 1 + 8x = –16 – 2x – 7x.
NeX [460]
Your answer is B. x= -1
3 0
3 years ago
What are the answers to these and how do I do it
nlexa [21]

Answer:

1. D

2.B

3.A

4.C

Step-by-step explanation:

You find where the line meets right on the “corner of the boxes” then count to the side then down or up to find the slope

6 0
3 years ago
100 POINTS!!!!
Sveta_85 [38]
Hey there! Sorry no one is answering! Definitely B!!
6 0
3 years ago
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