Hence, the horizontal velocity of the rover is 1.73 m/s
The forces of gravity between two objects are inversely proportional to
the square of the distance between them. So reducing the distance
by 1/2 means increasing the gravitational force by 2² = 4 times.
The 1 million newtons becomes 4 million newtons.
Note that this does NOT mean the satellite's altitude above the surface.
When you're calculating gravitational forces, it's the distance between
the centers of the objects. So the question is a meaningful exercise
only if we use the distance between the satellite and the planet's center.
Answer:
R = V ÷ I = 1.5V ÷ 0.01A = 150Ω
Explanation:
150 is the answer:)
Answer:
Normal force, N = 154.5 N
Explanation:
Given that,
Total mass of the cart, m = 20.4 kg
Angle of inclination, 
Distance moved, d = 20.1 m
The coefficient of kinetic friction between ground and cart is 0.6
The value of acceleration due to gravity, 
Let N is the normal force exerted on the cart by the floor. It is given by :




T = 103.23 N
So, the normal force is :

N = 154.5 N
So, the normal force exerted on the cart by the floor is 154.5 N. Hence, this is the required solution.