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Elena L [17]
3 years ago
7

Imagine that two balls, a basketball and a much larger exercise ball, are dropped from a parking garage. If both the mass and ra

dius of the exercise ball are 3 times larger than the mass and radius of the basketball, which of the two balls do you think will reach the ground first?
Physics
1 answer:
pashok25 [27]3 years ago
3 0

Here if we assume that there is no air friction on both balls then we can say

F = mg

now the acceleration is given as

F = ma = mg

a = g

so here both the balls will have same acceleration irrespective of size and mass

so we can say that to find out the time of fall of ball we can use

y = \frac{1}{2}gt^2

t = \sqrt{\frac{2y}{g}}

now from above equation we can say that time taken to hit the ground will be same for both balls and it is irrespective of its mass and size

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A 4.76 kg crate is suspended from the end of a short vertical rope of negligible mass. An upward force F(t) is applied to the en
Romashka-Z-Leto [24]

Answer:

The magnitude of the force is 64.634 newtons.

Explanation:

According to the statement, the crate is a constant mass system, whose upward force is described by the following expression:

F(t) = m\cdot \ddot{y} (t) (1)

Where:

F(t) - Force, in newtons.

m - Mass, in kilograms.

\ddot {y}(t) - Acceleration, in meters per square second.

The function acceleration is obtained by deriving the function position twice in time:

\dot y (t) = 2.80 + 1.83\cdot t^{2} (2)

\ddot y(t) = 3.66\cdot t (3)

And we expand (1) by applying (3):

F(t) = 3.66\cdot m \cdot t

Where t is the time, in seconds.

If we know that m = 4.76\,kg and t = 3.71\,s, then the magnitude of the force is:

F = 3.66\cdot (4.76)\cdot (3.71)

F = 64.634\,N

The magnitude of the force is 64.634 newtons.

6 0
3 years ago
Assume that a uniform magnetic field is directed into thispage. If an electron is released with an initial velocity directedfrom
Feliz [49]

Answer:

B). to the right

Explanation:

Since the direction of magnetic field is into the page

So here we know that

B = B_o(-\hat k)

now the velocity is from bottom to top

so we have

v = v_o \hat j

now the force on the moving charge is given as

\vec F = q(\vec v \times \vec B)

now we have

\vec F = (-e)(v_o \hat j \times B_o(-\hat k))

\vec F = e v_o B \hat i

so force will be towards Right

7 0
3 years ago
Definition of termperature in thermodynamics
antoniya [11.8K]
"Temperature is the measure of the average kinetic energy of the particles in a substance, which is related to how hot or cold that substance is. Historically, two equivalent concepts of temperature have developed, the thermodynamic description and a microscopic explanation based on statistical physics"
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3 years ago
6. And what's up with ChiN?
n200080 [17]
I don’t know what’s up with chin man ??
4 0
2 years ago
A 912-kg car is being driven down a straight, level road at a constant speed of 31.5 m/s. When the driver sees a police cruiser
sergejj [24]

Answer:

786.6 N

Explanation:

mass of car, m = 912 kg

initial velocity of car, u = 31.5 m/s

final velocity of car, v = 24.6 m/ s

time, t = 8 s

Let a be the acceleration of the car

Use first equation of motion

v = u + a t

24.6 = 31.5 + a x 8

a = - 0.8625 m/s^2

Force, F = mass x acceleration

F = 912 x 0.8625

F = 786.6 N

Thus, the force on the car is 786.6 N.

8 0
3 years ago
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