The volume in units of 6.03x10^3 in3
1ft = 12 inch
So to convert foot into inches we have to multiply by 12
The volume of container = 3.49ft^3
=3.49×12×12×12
= 6030.72 in^3
<h3>
What is the volume of a container?</h3>
The amount of space a container encloses, or how much room is inside of it, is measured by its volume. The volume of a box can be calculated using this straightforward formula: volume V = L × W × H for a box with height H, width W, and length L.
Many different units can be used, however because of the way this formula is written, the volume would have length to the third power dimensions. For instance, if the container's measurements are given in metres, the capacity of the box will be given in metres squared, or m3.
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Answer:
The wood's potential energy on the carpenter's shoulder is 150 J.
Explanation:
Given;
mass of the wood, m = 10 kg
height through which the wood was raised, h = 1.5 m
acceleration due to gravity, g = 10 m/s²
The wood's potential energy on the carpenter's shoulder is calculated as;
P.E = mgh
P.E = 10 x 10 x 1.5
P.E = 150 J
Therefore, the wood's potential energy on the carpenter's shoulder is 150 J.
Answer:
q = 8.57 10⁻⁵ mC
Explanation:
For this exercise let's use Newton's second law
F = ma
where force is magnetic force
F = q v x B
the bold are vectors, if we write the module of this expression we have
F = qv B sin θ
as the particle moves perpendicular to the field, the angle is θ= 90º
F = q vB
the acceleration of the particle is centripetal
a = v² / r
we substitute
qvB = m v² / r
qBr = m v
q =
The exercise indicates the time it takes in the route that is carried out with constant speed, therefore we can use
v = d / t
the distance is ¼ of the circle,
d =
d =
we substitute
v =
r =
let's calculate
r =
2 2.2 10-3 88 /πpi
r = 123.25 m
let's substitute the values
q =
7.2 10-8 88 / 0.6 123.25
q = 8.57 10⁻⁸ C
Let's reduce to mC
q = 8.57 10⁻⁸ C (10³ mC / 1C)
q = 8.57 10⁻⁵ mC
We can look at all the ages of the earth since it’s a big crack is reveals many layers of the earth and we can know about chemicals and metals that were in earth and diffrent times
Answer:
7.9060 m²
8.57 Volts
5.142×10⁻⁶ Joule
1.2×10⁻⁶ Coulomb
Explanation:
C = Capacitance between plates = 0.14 μF = 0.14×10⁻⁶ F
d = Distance between plates = 0.5 mm = 0.5×10⁻³ m
Q = Charge = 1.2 μC = 1.2×10⁻⁶ C
ε₀ = Permittivity = 8.854×10⁻¹² F/m
Capacitance

∴ Area of each plate is 7.9060 m²
Voltage

∴ Potential difference between the plates if the capacitor is charged to 1.2 μC is 8.57 Volts.
Energy stored
E=0.5CV²
⇒E = 0.5×0.14×10⁻⁶×8.57²
⇒E = 5.142×10⁻⁶ Joule
∴ Stored energy is 5.142×10⁻⁶ Joule
Charge
Q = CV
⇒Q = 0.14×10⁻⁶×8.57
⇒Q = 1.2×10⁻⁶ C
∴ Charge the capacitor carries before a spark occurs between the two plates is 1.2×10⁻⁶ Coulomb