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3 years ago

11

Graph x2 + 9y2 = 25. What are the domain and range? Someone please help me ! (Picture below)

1 answer:

Dahasolnce [82]3 years ago

4 0

The equation is equivalent to x2/25 + y2/(25/<span>9)</span>= 1, it is an ellipse equation
the center is C(0,0)
a=5; b= 5/3, so a>b it is a horizontal major axis type (the x-axis)
all that you do is to find all characteristics by following all required formula

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Simplify the following expression as much as you can use exponential properties. (6^-2)(3^-3)(3*6)^4

gtnhenbr [62]

Answer:

Simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

Step-by-step explanation:

We need to simplify the expression $(6^{-2})(3^{-3})(3*6)^4$

Solving:

$(6^{-2})(3^{-3})(3*6)^4$

Applying exponent rule: $a^{-m}=\frac{1}{a^m}$

$=\frac{1}{(6^{2})}\frac{1}{(3^{3})}(18)^4\\=\frac{(18)^4}{6^{2}\:.\:3^{3}} \\$

Factors of $18=2\times 3\times 3=2\times3^2$

Factors of $6=2\times 3$

Replacing terms with factors

$=\frac{(2\times3^2)^4}{(2\times 3)^{2}\:.\:3^{3}} \\=\frac{(2)^4\times(3^2)^4}{(2)^2\times (3)^{2}\:.\:3^{3}} \\$

Using exponent rule: $(a^m)^n=a^{m\times n}$

$=\frac{(2)^4\times(3)^8}{(2)^2\times (3)^{2}\:.\:3^{3}} \\=\frac{2^4\times 3^8}{2^2\times 3^{2}\:.\:3^{3}}$

Using exponent rule: $a^m.a^n=a^{m+n}$

$=\frac{2^4\times 3^8}{2^2\times 3^{2+3}}\\=\frac{2^4\times 3^8}{2^2\times 3^{5}}$

Now using exponent rule: $\frac{a^m}{a^n}=a^{m-n}$

$=2^{4-2}\times 3^{8-5}\\=2^{2}\times 3^{3}\\=4\times 27\\=108$

So, simplifying the expression $(6^{-2})(3^{-3})(3*6)^4$ we get $\mathbf{108}$

7 0

2 years ago

V = u + at<br> u = 2<br> a = -5<br> t = 1/2 (0.5)

Vsevolod [243]

$v = 2 + ( - 5 \times 0.5) \\ v = 2 - 0.5 \\ v = 1.5$

8 0

3 years ago

Which scales are equivalent to the scale 1cm to 5km? More than one is the right answer

Oduvanchick [21]

The answer would be A because each side is being multiplied by 3

8 0

3 years ago

Read 2 more answers

To factor 9x^2 - 4, you can first rewrite the expression as:

olga2289 [7]

Answer:

C. (3x)^2 - (2)^2

Step-by-step explanation:

Each of the two terms is a perfect square, so the factorization is that of the difference of squares. Rewriting the expression to ...

(3x)^2 - (2)^2

highlights the squares being differenced.

__

We know the factoring of the difference of squares is ...

a^2 -b^2 = (a -b)(a +b)

so the above-suggested rewrite is useful for identifying 'a' and 'b'.

4 0

3 years ago

Help me with the questions in the image

aliya0001 [1]

Answer:

12

96

9

38

25

Step-by-step explanation:

<h3>i.a+7 for a=5</h3>

5+7=12

<h3>ii.8(c+3) for c =9</h3>

8(9+3)

8(12)

96

<h3>iii.n+8 divided by 4 for n=28</h3>

=28+8 divided by 4

=36 divided by 4

=9

<h3>iv.6p+40 divided by 5 for p =5</h3>

=6×5+40 divided by 5

=30+40 divided by 5

=70 divided by 5

=38

<h3>v.3x+7 for x=6</h3>

=3×6+7

=18+7

=25

5 0

3 years ago