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2 years ago

7

What is the slope of a line parallel to the line y = 2x -1?

2 answers:

lbvjy [14]2 years ago

5 0

Answer: 2

Step-by-step explanation:

I did this question before

Nutka1998 [239]2 years ago

3 0

Answer:

2x

Step-by-step explanation:

aka 2

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If Maliyah won 25 games and llost 10 what would be the ratio for the games lost to total

Alla [95]

Answer:

10:35

Step-by-step explanation:

4 0

2 years ago

5. photo album: $25.50, 10% markup

sasho [114]

Answer:

$28.05

Step-by-step explanation:

If you want to find how much the photo album is after the markup, you first have to find 10% of the original price. 10% of $25.50 is $2.55, so you add $2.55 and $25.50 to find the price after the markup.

Hope this helps!

3 0

2 years ago

Suppose you have the following information. 12% of all drivers do not have a valid driver’s license, 6% of all drivers have no i

lubasha [3.4K]

Answer:

e) 0.14

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a driver does not have a valid driver's license.

B is the probability that a driver does not have insurance.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a driver does not have a valid driver's license but has insurance and $A \cap B$ is the probability that a driver does not have any of these things.

By the same logic, we have that:

$B = b + (A \cap B)$

We start finding these values from the intersection.

4% have neither

This means that $(A \cap B) = 0.04$

6% of all drivers have no insurance

This means that $B = 0.06$ . So

$B = b + (A \cap B)$

$0.06 = b + 0.04$

$b = 0.02$

12% of all drivers do not have a valid driver’s license

This means that $A = 0.12$

So

$A = a + (A \cap B)$

$0.12 = a + 0.04$

$a = 0.08$

The probability that a randomly selected driver either fails to have a valid license or fails to have insurance is about

$P = a + b + (A \cap B) = 0.08 + 0.02 + 0.04 = 0.14$

So the correct answer is:

e) 0.14

8 0

2 years ago

Gcf using prime factorization of 52 and 65

Leto [7]

<span>25: 2 × 2 × 13 65: 5 × 13</span>

3 0

3 years ago

A particle is moving along the x-axis so that its position at t ≥ 0 is given by s(t)=(t)ln(5t). Find the acceleration of the par

lyudmila [28]

Answer:

$a(\frac{1}{5e})=5e$

Step-by-step explanation:

we are given equation for position function as

$s(t)=tln(5t)$

Since, we have to find acceleration

For finding acceleration , we will find second derivative

$s'(t)=\frac{d}{dt}\left(t\ln \left(5t\right)\right)$

$=\frac{d}{dt}\left(t\right)\ln \left(5t\right)+\frac{d}{dt}\left(\ln \left(5t\right)\right)t$

$=1\cdot \ln \left(5t\right)+\frac{1}{t}t$

$s'(t)=\ln \left(5t\right)+1$

now, we can find derivative again

$s''(t)=\frac{d}{dt}\left(\ln \left(5t\right)+1\right)$

$=\frac{d}{dt}\left(\ln \left(5t\right)\right)+\frac{d}{dt}\left(1\right)$

$=\frac{1}{t}+0$

$a(t)=\frac{1}{t}$

Firstly, we will set velocity =0

and then we can solve for t

$v(t)=s'(t)=\ln \left(5t\right)+1=0$

we get

$t=\frac{1}{5e}$

now, we can plug that into acceleration

and we get

$a(\frac{1}{5e})=\frac{1}{\frac{1}{5e}}$

$a(\frac{1}{5e})=5e$

5 0

3 years ago