Answer:
10:35
Step-by-step explanation:
Answer:
$28.05
Step-by-step explanation:
If you want to find how much the photo album is after the markup, you first have to find 10% of the original price. 10% of $25.50 is $2.55, so you add $2.55 and $25.50 to find the price after the markup.
Hope this helps!
Answer:
e) 0.14
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
A is the probability that a driver does not have a valid driver's license.
B is the probability that a driver does not have insurance.
We have that:

In which a is the probability that a driver does not have a valid driver's license but has insurance and
is the probability that a driver does not have any of these things.
By the same logic, we have that:

We start finding these values from the intersection.
4% have neither
This means that 
6% of all drivers have no insurance
This means that
. So



12% of all drivers do not have a valid driver’s license
This means that 
So



The probability that a randomly selected driver either fails to have a valid license or fails to have insurance is about

So the correct answer is:
e) 0.14
<span>25: 2 × 2 × 13 65: 5 × 13</span>
Answer:

Step-by-step explanation:
we are given equation for position function as

Since, we have to find acceleration
For finding acceleration , we will find second derivative




now, we can find derivative again




Firstly, we will set velocity =0
and then we can solve for t

we get

now, we can plug that into acceleration
and we get

