Let
x-------> the number of dinner
y-------> the number of lunch
we know that
-------> equation A
------> equation B
Substitute equation B in equation A
![8[y]+5y \leq 42](https://tex.z-dn.net/?f=8%5By%5D%2B5y%20%5Cleq%2042)
so
the greatest number of lunch is 
Hence
the greatest number of dinner is 
therefore
the greatest number of meals is
<u>the answer is</u>
Answer:
Center: (-5,10)
Radius: 2
Step-by-step explanation:
The equation of the circle in center-radius form is:
Where the point (h,k) is the center of the circle and "r" is the radius.
Subtract 121 from both sides of the equation:
Add 10x to both sides:
Make two groups for variable "x" and variable "y":
Complete the square:
Add 
inside the parentheses of "x".
Add 
inside the parentheses of "y".
Add 
and 
to the right side of the equation.
Then:
Rewriting, you get that the equation of the circle in center-radius form is:
You can observe that the radius of the circle is:
And the center is:
Answer:
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Step-by-step explanation:
Answer:
20 passengers at $960 each
Step-by-step explanation:
Assuming at least 20 people sign up for the cruise, determine how many passengers will result in the maximum revenue for the owner of the yacht.
(a) Find a function R giving the revenue per day realized from the charter.
R(x) =
(b) What is the revenue per day if 48 people sign up for the cruise?
$
(c) What is the revenue per day if 78 people sign up for the cruise?
$
revenue (R) = (20+x)(960-8x)
= 19200 - 160x + 960x -8 x^2
dR/dx = -160 + 960 - 16x = 0 for a max of R
16x = 800
x = 50
It’s A, because you have to multiply both sides by 2 to isolate the variable x.
