Answer:
16
Step-by-step explanation:
We can see that Ar is the perpendicular bisector of chord BD. Since A is the center of the circle, AR is the radius of the circle, which is 10 (6+4)
Next, we can see that when we connect point A to point D, it is also a radius. Thus, AD is also equal to 10 as the radius of the circle remains the same.
Using Pythagoras theorem, a^2 + b^2 = c^2, we can make a right angled triangle of ACD.
AC = 6 = a
CD = ? = b
AD = 10 = c
10^2 = 6^2 + b^2
b^2 = 10^2 - 6^2 = 64
b = CD = 8
Now, since Ar is the perpendicular bisector of chord BD, BD = CD x 2
BD = 8 x 2 = <u>16</u>
Answer:
In an isosceles right triangle, the hypotenuse is larger than the sides by a factor of the square root of 2.
So, if the hypotenuse is 8 then the sides are 8 / (sq root of 2) = 5.6568542495
Step-by-step explanation:
Answer:
(-(7-9))(z)-6z= 8(-6+2)
Simplify
-(-2)(z) -6z =8(-6+2)
Multiply 8*-6 and 8*2
2z -6z= -48+16
Combine like terms
2z+-6z =-32
-4z=-32
Divide both sides by -4
z=8
Step-by-step explanation:
Answer:
OOF
Step-by-step explanation:
