<u>Answer:</u> The mass of phosphorus that is present for given amount of calcium is 28.53 g.
<u>Explanation:</u>
We are given:
Mass of calcium = 50 grams
The chemical formula of calcium phosphate is
Molar mass of calcium = 40 g/mol
Molar mass of phosphorus = 31 g/mol
In 1 mole of calcium phosphate, 120 grams of calcium is combining with 62 grams of phosphorus.
So, 50 grams of calcium will combine with = of phosphorus.
Hence, the mass of phosphorus that is present for given amount of calcium is 28.53 g.
Answer:
The answer to your question is : 16.9 g of Ag
Explanation:
Data
26 g Ag
10.8 g of Sn
2.4g Cu
0.8 Zn
Ag = ? in 26 g of sample
Total mass in the amalgam = 26 + 10.8 + 2.4 + 0,8 = 40 g
Rule of three
40 g of sample -------------- 26 g of silver
26 g of sample -------------- x
x = (26 x 26) / 40
x = 16.9 g of Silver
16)position
17)starting point
19)balanced, are different, balanced, unbalanced
An element is a substance made from only one type of atom (e.g. oxygen is an element made up of only oxygen atoms).
An atom is the simplest form of an element that can exist, such as a lithium atom (Li).
Atoms of different elements can be combined together to create compounds, e.g sodium oxide (Na2O).
A molecule is a combination of 2 or more atoms that form chemical bonds. When these atoms are of the same element, they can be called molecules (e.g. O3 - ozone).
However when a molecule is made up of atoms of different elements, they are classified as compounds (e.g. CO2 - carbon dioxide).
So all compounds are molecules, but not all molecules are compounds.
Answer:
Explanation:
BrO3- (aq) + Sb^3+ (aq) --------> Br^3- (aq) + Sb^5+ (aq) is an unbalanced equation and needs to be balanced
BrO3- (aq) → Br^3- (aq
to balance it water must be added to the right side and H⁺ be added to the left side
BrO₃⁻ + 6 H⁺ + 8e⁻ → Br³⁻ + 3 H₂ O
Sb³⁺ (aq) → Sb⁵⁺ + 2e⁻
multiply the second equation by 4
BrO₃⁻ + 6 H⁺ + 8e⁻ → Br³⁻ + 3 H₂ O
4Sb³⁺ → 4Sb⁵⁺ + 8 e⁻
add the two equation together and cancel the 8 e electrons on both side
BrO₃⁻ + 4Sb³⁺ + 6 H⁺ → Br³⁻ + 4Sb⁵⁺ + 3 H₂ O
number of mole of BrO₃⁻ = volume in liters × molarity = (29.9 / 1000) L × 0.120 M = 0.003588 moles
from the balanced equation of reaction;
one mole of BrO₃⁻ requires 4 moles of Sb³⁺
0.003588 moles of BrO₃⁻ will require = 0.003588 × 4 = 0.0144 moles of Sb³⁺
a) amount of antimony in grams in the sample = 0.0144 moles × 121.8 g ( molar mass of antimony) = 1.748 g
b ) percentage of antimony in the ore = 1.748 g / 6.33 g = 27.62 %