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Anettt [7]
2 years ago
6

When 20.4g of sodium metal are mixed with chlorine gas, are 52.0 g of sodium chloride

Chemistry
2 answers:
m_a_m_a [10]2 years ago
8 0

Explanation:

The answer: True

I explained the answer to your question in the submitted photo

vagabundo [1.1K]2 years ago
6 0

Answer: True

Explanation:

\mathrm{The\ balanced \ chemical \ equation\ is\ :}\\$2 \mathrm{Na}{(s)}+\mathrm{Cl}_{2}(g) \rightarrow 2 \mathrm{NaCl}(s)

<u>For Na</u>

\\$Given mass $=20.4 \mathrm{~g}$ \ \ Molecular mass $=23 \mathrm{~g}\ \ $Number of moles $=\frac{\text { Given mass }}{\text { Molecular mass }}$$$\begin{aligned}&=\frac{20.4}{23} \\&=0.887 \text { moles }\end{aligned}$$Stoichiometric ratio of $\mathrm{Na}$ is same as that of $\mathrm{NaCl}$ i.e., $1: 1$.$\therefore$ Moles of $\mathrm{NaCl}=0.887$ motes

<u>For NaCl</u>

$$\\\begin{aligned}\text { Molecular mass } &=23+35.5 \\&=58.5 \mathrm{~g}\end{aligned}$$

\begin{aligned}\\& $\therefore$ Mass of $\mathrm{NaCl}$ produced will be=\text { No.of moles } \times \text { Molecular mass } \\&=0.887 \times 58.5 \\&=51.9 \\&\simeq 52 \mathrm{~g} \quad\end{aligned}$$

Therefore, it is true that when 20.4g of sodium metal are mixed with chlorine gas, 52.0 g of sodium chloride is produced

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Sedbober [7]

Explanation:

If water is ice-form, only the gap between molecules reduces but the molecule remains the same. The gap between liquid water molecules is greater than that between the molecules. That's why ice is thinner than water.

The intermolecular gap now increases in the gaseous form, which makes it less heavier than solid ice and liquid water. However, the molecule still remain the same.

4 0
3 years ago
Complete and balance the following equation:
sertanlavr [38]
You need to add the last substance to the products side(the right sode of the arrow). You have hydrogen and oxygen - water.

You get: BrO3 + N2H4 -> Br2 + N2 + H2O

# of Br: 1x1 = 1 # of Br: 2x1 = 2
O: 3x1 = 3 O: 1x1 = 1
N: 2x1 = 2 B N: 2x1 = 2
H: 4x1 = 4. H: 2x1 = 2

Br:
Multiply the reactant (left) side by 2 to balance.

O:
You've just multiplied the reactant oxygen by 2 so now the reactant side equals 6. Multiply the product (right) side by six as well.

H:
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N:
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You end up with the complete and balanced equation:

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4 0
4 years ago
When a metal and a non-metal react, the ____ tends to lose electrons and the ____ tends to gain electrons?
valentina_108 [34]
<span>When a metal and a non-metal react, the metal tends to lose electrons and the non metal tends to gain electrons?</span>
8 0
3 years ago
Can somebody help me please :)
juin [17]
Not sure but i'll say D
4 0
3 years ago
Read 2 more answers
Can some one please help me with this question with the steps please, thanks in advance ​
tekilochka [14]

The molecular formula for Hydrocarbon =  C₄H₁₀

<h3>Further explanation:</h3>

Given

50 ml hydrocarbon

200 ml CO₂

250 ml H₂O

Required

The molecular formula of Hydrocarbon

Solution

From Avogadro's hypothesis, at the same temperature and pressure, the ratio of gas volume will be equal to the ratio of gas moles  

So moles Hydrocarbon : CO₂ : H₂O = 50 ml : 200 ml : 250 ml = 1 : 4 : 5

mol C in 1 mol CO₂=1, and for 4 moles CO₂ there are 4 moles C

mol H in 1 mol H₂O =2, and for 5 moles H₂O there are 10 moles H

So mol ratio C : H in compound = C₄H₁₀

4 0
3 years ago
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