In solid methane, the forces between neighboring CHA molecules are best characterized as

An inefficient appliance costs less to operate than an efficient one, because it takes more energy to do the same job.

Nesterboy [21]

An inefficient appliance costs less to operate than an efficient one, because it takes more energy to do the same job is "False".

Answer: Option B

Explanation:

Energy efficiency is about utilizing less energy consuming appliances than inefficient appliance which consume more energy to do the similar job and support for avoiding high energy bills and unnecessary pollution in the process.

The choice for energy efficiency is "ENERGY STAR LABEL" makes it known to consumers or businesses that a product, home or building is more energy efficient than others on the market.

ENERGY STAR and its partners have managed to save nearly 4 trillion kilowatt-hours of electricity from American families and businesses in 2017 and resulted into 3 billion metric tons of greenhouse gas reductions.

4 0

4 years ago

Please fast!!!!!!!!!!!!!!!!!!!!!!

monitta

Answer:

1 g/mL.

Explanation:

From the question given above, the following data were obtained:

Volume = 100 mL

Mass = 100 g

Density =?

Density of a substance is simply defined as the mass of the substance per unit volume of the substance. The density can be expressed mathematically as:

Density (D) = mass (m) / volume (V)

D = m / V

With the above formula, we can obtain the density of the liquid as follow:

Volume (V) = 100 mL

Mass (m) = 100 g

Density (D) =?

D = m / V

D = 100 / 100

D = 1 g/mL

Thus, the density of the liquid is 1 g/mL

5 0

3 years ago

A monatomic ideal gas that is initially at 1.50 * 105 Pa and has a volume of 0.0800 m3 is compressed adiabatically to a volume o

lubasha [3.4K]

Answer:

300000Pa or 3×10^5 Pa

Explanation:

Since the problem involves only two parameters of volume and pressure, the formula for Boyle's law is suitably used.

Using Boyle's law

P1V1 = P2V2

P1 is the initial pressure = 1.5×10^5Pa

V1 is the initial volume = 0.08m3

P2 is the final pressure (required)

V2 is the final volume = 0.04 m3

From the formula, P2 = P1V1/V2

P2 = 1.5×10^5 × 0.08 ÷ 0.04

= 300000Pa or 3×10^5 Pa.

8 0

3 years ago

Calculate the amount of heat released in the combustion of 10.5 grams of Al with 3 grams of O2 to form Al2O3(s) at 25°C and 1 at

ElenaW [278]

Answer : The amount of heat released in the combustion is, 209.5 kJ

Explanation :

First we have to calculate the moles of Al and $O_2$ .

$\text{ Moles of }Al=\frac{\text{ Mass of }Al}{\text{ Molar mass of }Al}=\frac{10.5g}{27g/mole}=0.389moles$

$\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{3g}{32g/mole}=0.188moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction will be:

$4Al+3O_2\rightarrow 2Al_2O_3$

From the balanced reaction we conclude that

As, 3 mole of $O_2$ react with 4 mole of $Al$

So, 0.188 moles of $O_2$ react with $\frac{4}{3}\times 0.188=0.251$ moles of $Al$

From this we conclude that, $Al$ is an excess reagent because the given moles are greater than the required moles and $O_2$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $Al_2O_3$