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ollegr [7]
3 years ago
14

A plane loses altitude at the rate of 5 meters per second. It begins with an altitude of 8500 meters. The planes altitude is a f

unction of the number of seconds that pass. How much time will pass before the plane will land
Mathematics
1 answer:
myrzilka [38]3 years ago
3 0

Answer:

28.33 min

Step-by-step explanation:

altitude = 8500 m - (5 m/sec)t

To determine the length of time that will pass before the plane will land, set this altitude function = to 0 and solve for t:  This assumes that "land" is at sea level.

(5 m/sec)t = 8500 m

t = (8500 m) / (5 m/sec) = 1700 sec, or 28.33 min (since 60 sec = 1 min)

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Harman [31]
We are looking for the probability :
P(X > n)=0.05
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The above formula is equivalent to this one:
P(\dfrac{X-545}{100}< \dfrac{n-545}{100})=0.95
From normal law table, we read the value of \dfrac{X-545}{100}.
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5 0
3 years ago
A can of killa kola contains 3/8 qt. Kyle drinks 6 cans. How much did he drink? Please explain.
nevsk [136]

Answer:

He drank  2¹/₄qt of 6 cans

Step-by-step explanation:

A can of killa kola contains 3/8 qt.

Kyle drinks 6 cans.

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6 0
3 years ago
I need help on this and more so can sb help me ?..
nignag [31]

Answer:

Its the 2nd one

Step-by-step explanation:

Simplify the exponents and then multiply

4 0
3 years ago
Evaluate log2 1 over 64.
Nastasia [14]
Let log2 (1/64) = x. Then,

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2^x = 2^(-6)

So,

x = -6

log2 (1/64) = -6 <----- this is the answer.


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6 0
3 years ago
Evaluate: 8 * 6+ (12 - 4) + 2
wlad13 [49]

Answer:

58

Step-by-step explanation:

8*6+(8)+2

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7 0
3 years ago
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