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2 years ago

20 POINTS!! Let logb A = 3; log, C = 2; log, D= 5 What is the value of logb(a5c2/d6)?

Mathematics

1 answer:

mariarad [96]2 years ago

4 0

Answer:

-11

Step-by-step explanation:

logb ( a^5 c^2 / d^6)

Splitting these into log (xy/z) = log x + log y - logz

logb ( a^5) +logb ( c^2) - logb( d^6)

We also know that log x^y = y log x

5logb ( a) +2logb ( c) - 6 logb( d)

Given logb ( a)=3 logb ( c) =2 logb( d)=5

5 * 3 + 2* 2 - 6* 5

15 +4 -30

19 - 30

-11

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3 years ago

Ariel was playing basketball. 1 of her shots went in the hoop. 2 of her shots did not going the hoop. how many shots were there

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3 years ago

Read 2 more answers

Solve and show work: <br> f(300) = 90 + 0.11x

Vinil7 [7]

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6 0

3 years ago

3. From the table below, find Prof. Xin expected value of lateness. (5 points) Lateness P(Lateness) On Time 4/5 1 Hour Late 1/10

wariber [46]

Answer:

The expected value of lateness $\frac{7}{20}$ hours.

Step-by-step explanation:

The probability distribution of lateness is as follows:

Lateness P (Lateness)

On Time 4/5

1 Hour Late 1/10

2 Hours Late 1/20

3 Hours Late 1/20

The formula of expected value of a random variable is:

$E(X)=\sum x\cdot P(X=x)$

Compute the expected value of lateness as follows:

$E(X)=\sum x\cdot P(X=x)$

$=(0\times \frac{4}{5})+(1\times \frac{1}{10})+(2\times \frac{1}{20})+(3\times \frac{1}{20})\\\\=0+\frac{1}{10}+\frac{1}{10}+\frac{3}{20}\\\\=\frac{2+2+3}{20}\\\\=\frac{7}{20}$

Thus, the expected value of lateness $\frac{7}{20}$ hours.

8 0

3 years ago

Find the value of the following expression:

Illusion [34]

Ok, so first you solve whatever is in the parentheses.
(28 • 5-5 • 190)-2•228
28• 5 = 140
Then 5 •190 = 950
Then multiply 950 • 140 = 133,000
Then it should look like this:
133,000-2•228
Multiply 2 • 228 = 456
Then subtract 456 from 133,000.
The answer should come out to 132,544.

3 0

3 years ago