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algol [13]
3 years ago
15

What is the vertex form of the equation?

Mathematics
1 answer:
Oxana [17]3 years ago
4 0

Answer:

- (x - 6)^2 + 32

Step-by-step explanation:

-x^2 + 12x- 4

= - (x^2 - 12x) - 4

= - [(x - 6)^2 - 36) - 4

= -(x - 6)^2 + 32

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Answer:

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Step-by-step explanation:

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s = ut + \frac{1}{2}at^{2}

where s is the total displacement, u the initial velocity, t the time travelled, and a is the acceleration.

given u = 48 ft/s, and a = acceleration due to gravity g = -9.8\frac{m}{s^{2}}

1 m = 3.28 feet therefore g becomes -9.8×3.28\frac{ft}{s^{2}}

here negative sigh comes as acceleration due to gravity is in opposite direction of initial velocity.

therefore f(t) becomes f(t) = 48t-16.07t^{2}

to find max height we should find differentiation of f(t) and equate it to 0

therefore we get 48 = 32.144t

t = 1.49 s

therefore max height f(1.49) = 71.67-36.67 = 35 feet

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3 years ago
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