Answer:
13.07
Step-by-step explanation:
Subtraction dude.
Answer:
A. Similar using SAS; ∆ABC ~ ∆DFE
Step-by-step explanation:
m<B of ∆ABC = m<F of ∆DFE
AB corresponds to DF
AB/DF = 12/8 = 3/2
BC corresponds to FE
BC/FE = 24/16 = 3/2
Thus, the ratio of the corresponding sides of both triangles are the same. Therefore, both triangles has two sides that are proportional to each other, and also had an included corresponding angles that are congruent to each other.
By the SAS criterion, we can conclude that both triangles are similar to each other. That is, ∆ABC ~ ∆DFE
Answer:5p^3-2p^2-7p+1
Step-by-step explanation:
-3p^3+5p+(-2p^2)+(-4)-12p+5-(-8p^3)
open brackets
-3p^3+5p-2p^2-4-12p+5+8p^3
Collect like terms
-3p^3+8p^3-2p^2+5p-12p-4+5
5p^3-2p^2-7p+1
Answer:
Option A. one rectangle and two triangles
Option E. one triangle and one trapezoid
Step-by-step explanation:
step 1
we know that
The area of the polygon can be decomposed into one rectangle and two triangles
see the attached figure N 1
therefore
Te area of the composite figure is equal to the area of one rectangle plus the area of two triangles
so
![A=(8)(4)+2[\frac{1}{2}((8)(4)]=32+32=64\ yd^2](https://tex.z-dn.net/?f=A%3D%288%29%284%29%2B2%5B%5Cfrac%7B1%7D%7B2%7D%28%288%29%284%29%5D%3D32%2B32%3D64%5C%20yd%5E2)
step 2
we know that
The area of the polygon can be decomposed into one triangle and one trapezoid
see the attached figure N 2
therefore
Te area of the composite figure is equal to the area of one triangle plus the area of one trapezoid
so
