Answers:
CB = 14
GF = 8
FB = 9
EF is parallel to CB
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Explanations:
Points E and F are midpoints of their respective sides. They form the midsegment EF. Because EF is a midsegment, A midsegment is half the length of its parallel counterpart, so CB is two times longer than EF. If EF is 7 units long, then CB = 2*EF = 2*7 = 14
For similar reasons, GF is parallel to AC. If AC = 16, then half of that is GF = (1/2)*AC = 0.5*16 = 8.
FB = FA = 9 as these segments have the same single tickmark to indicate they are the same length
EF is parallel to CB because EF is a midsegment, and this is one of the properties of being a midsegment. We can show that quadrilateral EGBF is a parallelogram to help prove this.
Answer:
B 26.3% increase
Step-by-step explanation:
1 - 3.50/4.75 = .263 = 26.3%
Answer:
X1=-4+4i
X2=-4-4i
Step-by-step explanation:
X^2+8x+32=0
Δ=b^2-4ac=8^2-4(32)=-64<0
X1=(-b-i√Δ) /2a=(-8-8i)/2=-4-4i
X2=(-b+i√Δ) /2a=(-8+8i)/2=-4+4i
Answer:
Option C
Step-by-step explanation:
When you put the write the scenario in an equation, it'll look like
(5q+3)(5q-3) for the new width times the new length
Factor these, and you shall get 25q^2+15q-15q-9. Simplify that into
25q^2-9
Answer:
We conclude that:
f(a) + 5 = a² + 8a - 5
Step-by-step explanation:
Given
The function is given by
f(x) = x²+8x-10
To determine
f(a)+5
In order to determine f(a)+5, first, we need to determine f(a).
Now substitute x = a in the function f(x) = x²+8x-10
f(a) = (a)² + 8(a) - 10
f(a) = a² + 8a - 10
Thus,
f(a) + 5 = (a² + 8a - 10) + 5
f(a) + 5 = a² + 8a - 5
Therefore, we conclude that:
f(a) + 5 = a² + 8a - 5
