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Serjik [45]
3 years ago
8

John concludes that the probability of drawing a dime from a jar containing 40 dimes and 40 nickles is 0.5. Which experiment jus

tifies Johns conclusion?
Mathematics
1 answer:
White raven [17]3 years ago
8 0
John assumed that out of 80 coins contained in the Jar, 40 coin pieces is a dime, which makes 40 out of 80 equal to 0.5. But this assumption is wrong as for each draw you'd only have 1/80 chance of getting a dime combining and giving both types of coin each a chance to be drawn.
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the number of women at a training workshop was two less than three times the number of men if 50 people attended the workshop ho
Anton [14]
Answer: 148

Work: 50 men multiplied by 3 =150
If there is two less women from 3 multiplied by 50 (150) , then 150 - 2 = 148
6 0
3 years ago
Use co.patible numbers to find two estimates 73÷4,858
Svet_ta [14]
NO.2 answer is 5088.052869
6 0
3 years ago
Please explain I need help with all these
sergey [27]
For all of these you're trying to solve for the variable. The variable is usually a number or symbol.

11) -44+n=36
Step one would be to add 44 to both sides of the equation.

N=80

12) -36=p-91
Step one would be to add -91 to both sides of the equation.

P=55

13) X-225=671
Step one you be to add 225 to both sides of the equation. Although it may seem difficult because of the big numbers, it's the same technique.

14) 19=c-(-12)
Step one on this equation will be a little different. Because there are two negative signs (-), they turn into a plus sign. Remember, two negative signs make a positive sign.

19=c+12

Now you just subtract 12 from each side of the equation.

6=C
3 0
3 years ago
An accessories store sells $8 custom socks and $11 custom hats. If 11 items were sold on Monday, and the
Vanyuwa [196]

Answer:

7 socks were sold

Step-by-step explanation:

7*8=56

11-7=4

4×11=44

56+44=100

This proves the answer of 7 to be correct

7 0
2 years ago
A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w
melamori03 [73]

Answer:

The hypothesis is:

<em>H₀</em>: p_{X}-p_{Y}=0.

<em>Hₐ</em>: p_{X}-p_{Y}.

Step-by-step explanation:

Let <em>X</em> = number of men who exercise regularly and <em>Y</em> = number of women who exercise regularly.

The information provided is:

n_{X}=150\\X=88\\n_{Y}=200\\Y=130

Compute the sample proportion of men and women who exercise regularly as follows:

\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587

\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and \hat p_{X}=0.587.

The random variable <em>Y</em> also follows a Binomial distribution with parameters <em>n</em> = 200 and \hat p_{Y}=0.65.

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

\hat p=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.

A two proportion <em>z</em>-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.

The hypothesis for this test cab be defined as:

<em>H₀</em>: The proportion of women is same as men who exercise regularly, i.e. p_{X}-p_{Y}=0.

<em>Hₐ</em>: The proportion of women is more than men who exercise regularly, i.e. p_{X}-p_{Y}.

6 0
3 years ago
Read 2 more answers
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