9514 1404 393
Answer:
3. vertical stretch by a factor of 2; shift right 1 and down 1
4. shift left 4 and up 4 (no stretch or shrink)
Step-by-step explanation:
The vertex form equation is ...
y = a(x -h)^2 +k
It represents a vertical stretch of the parent function by a factor of 'a', a right shift of 'h', and an upward shift of 'k'.
Compare the the given equations to the above form to see the transformations.
__
3. (a, h, k) = (2, 1, -1) ⇒ vertical stretch by a factor of 2; shift right 1, down 1
4. (a, h, k) = (1, -4, 4) ⇒ no vertical stretch; shift left 4, up 4
Answer:
plz put one qusetion a time plz so i can put it down better
Step-by-step explanation:
Answer:
8-6i
Step-by-step explanation:
complex number in standard form will be in the form of a+bi
(-2 − 2i) + (10 − 4i) , open parenthesis
-2- 2i +10 -4i, group like terms
-2+10 -2i -4i, combine like terms
8 - 6i
Answer: D, 6km/hr.
Step-by-step explanation:
Heather can finish a 12-kilometer race in 2 hours, and now we have to find how many kilometers she can ride/run at in 1 hour.
How many hours can Heather run in 1 hour? To solve that, we can use the equation 12 ÷ 2.
12 ÷ 2 = 6.
Therefore, if Heather keeps her pace constant, then her rate will be 6km/hr, or D.
Answer:
The probability that a defective rod can be salvaged = 0.50
Step-by-step explanation:
Given that:
A machine shop produces heavy duty high endurance 20-inch rods
On occasion, the machine malfunctions and produces a groove or a chisel cut mark somewhere on the rod.
If such defective rods can be cut so that there is at least 15 consecutive inches without a groove.
Then; The defective rod can be salvaged if the groove lies on the rod between 0 and 5 inches i.e ( 20 - 15 )inches
Now:
P(X ≤ 5) = 
= 0.25
P(X ≥ 15) =
= 0.25
The probability that a defective rod can be salvaged = P(X ≤ 5) + P(X ≥ 15)
= 0.25+0.25
= 0.50
∴ The probability that a defective rod can be salvaged = 0.50
