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elixir [45]
4 years ago
8

PLEASE HELP ME ON NUMBER ONE

Mathematics
1 answer:
ladessa [460]4 years ago
3 0
Use math papa it helped me
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What is the slope of (1,0) and (3, 4) (remember to use the slope formula y1-y2/x1-x2<br> and reduce)
expeople1 [14]

Answer:

m=2

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS

<u>Alg I</u>

  • Slope Formula: m=\frac{y_2-y_1}{x_2-x_1}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (1, 0)

Point (3, 4)

<u>Step 2: Find slope </u><em><u>m</u></em>

  1. Substitute:                    m=\frac{4-0}{3-1}
  2. Subtract:                       m=\frac{4}{2}
  3. Divide:                          m=2
4 0
3 years ago
Find all solutions of the equation sec 4 x − 2 = 0
Anuta_ua [19.1K]
Let's solve your equation step-by-step.
4x−2=0
Step 1: Add 2 to both sides.
4x−2+2=0+2
4x=2
Step 2: Divide both sides by 4.
4x
4
=
2
4
x=
1
2

Answer:
x=
1
2
hope it helps
7 0
3 years ago
Please don’t skip this is due tonight
4vir4ik [10]

Answer:

I think no more that 13 bags($19.5) with 104 apples? Check it

Step-by-step explanation:

<h3>20/1.50=13.333 or 13 and then 13 x 8=104</h3>
6 0
4 years ago
A small car can hold 50 liters of gas. How many milliliters is that?
ololo11 [35]
One liter is 1000 milliliters.  This means that 50 liters is 50*1000 milliliters or 50,000 mL.
6 0
3 years ago
Read 2 more answers
a building with a height of 32m casts a shadow that is 20m long. a person standing casts a shadow that is 1.2 m long how tall is
wlad13 [49]
Most of the information's required for solving the question is already given in the question.
Height of the building that casts a shadow of 20 m = 32 m
Then
Height of the man that casts a shadow of 1.2 m = (32/20) * 1.2 meter
                                                                             = 3.2 * 1.2 meter
                                                                             = 3.84 meter
So the actual height of the person casting a shadow of 1.2 meter is 3.84 meters. I hope that the procedure used for solving the problem is easy enough for you to understand. You can definitely use this method in future for solving problems of similar type without requiring any additional help from outside.

6 0
4 years ago
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