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2 years ago

9

A class of 20 students is visiting the fair today. Each student is 16 years old or younger and will participate in

2 answers:

Finger [1]2 years ago

8 0

Answer:

C.) The Hay Bale Toss would be more skewed.

Step-by-step explanation:

mr Goodwill [35]2 years ago

5 0

Answer:

The interval of 0-19 will increase by 20 of either Hay Bale Toss or Pie Eating Contest.

Step-by-step explanation:

Number of students visiting the fair = 20

Age group = 0-16

In the histogram, this age group falls in the first interval which is 0-19.

If all 20 students joined the Hay Bale Toss then the bar of 0-19 of Hay Bale Toss will increase from 40 to 60 and the graph of Pie Eating Contest will remain the same.
If all 20 students joined the Pie Eating Contest then the bar of 0-19 of Hay Bale Toss will increase from 20 to 40 and the graph of Hay Bale Toss will remain the same.

<em>Therefore, only one if the graph's interval of 0-19 will increase by 20 whereas the other graph would remain the same.</em>

!!

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Answer:

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Step-by-step explanation:

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2 years ago

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3 years ago

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Step-by-step explanation:

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2 years ago

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Answer:

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Replacing the info given we got:

$t=\frac{9.41-9.33}{\frac{0.24}{\sqrt{81}}}=3$

Step-by-step explanation:

Information given

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$s=0.24$ represent the sample standard deviation

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$\mu_o =9.33$ represent the value to verify

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

Hypothesis to test

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Alternative hypothesis: $\mu > 9.33$

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Replacing the info given we got:

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Step-by-step explanation:

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