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babunello [35]
3 years ago
9

A class of 20 students is visiting the fair today. Each student is 16 years old or younger and will participate in

Mathematics
2 answers:
Finger [1]3 years ago
8 0

Answer:

C.) The Hay Bale Toss would be more skewed.

Step-by-step explanation:

mr Goodwill [35]3 years ago
5 0

Answer:

The interval of 0-19 will increase by 20 of either Hay Bale Toss or Pie Eating Contest.

Step-by-step explanation:

Number of students visiting the fair = 20

Age group = 0-16

In the histogram, this age group falls in the first interval which is 0-19.

  • If all 20 students joined the Hay Bale Toss then the bar of 0-19 of Hay Bale Toss will increase from 40 to 60 and the graph of Pie Eating Contest will remain the same.
  • If all 20 students joined the Pie Eating Contest then the bar of 0-19 of Hay Bale Toss will increase from 20 to 40 and the graph of Hay Bale Toss will remain the same.

<em>Therefore, only one if the graph's interval of 0-19 will increase by 20 whereas the other graph would remain the same.</em>

!!

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Answer:

Step-by-step explanation:

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3 0
2 years ago
you are painting to sell at a carnival .it takes you 3 hours to paint a small pictures and 4 hours to paint a large picture.you
zvonat [6]
3 hours for small = 3s
4 hours for large = 4b
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Hope this helps :)
5 0
3 years ago
Poison Ivy had $17.34 in her account. She wrote a check for $24.86. What will her account balance be when the check is cashed? F
Ierofanga [76]

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Step-by-step explanation:

5 0
3 years ago
Brockman Corporation's earnings per share were $3.50 last year, and its growth rate during the prior 5 years was 7.0% per year.
fredd [130]

Answer:

The number of years it would take is  n  =  2 \ years

Step-by-step explanation:

From the question we are told that

         The earning per share  is  P = $3.50

          The growth rate is  r  =  7.0%

           The duration is t =  5 \ years

Generally the future value is mathematically represented as

          A =  P(1 + \frac{r}{100} )^n

 Where P is the present value

              n is the time period

         A is the future value which is mathematically evaluated as

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substituting value

            A =  3 * 3.50

            A = $ 10.5 0

So

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       10.5 =  3.5(1 + \frac{7}{100} )^n

       10.5 = 3.225^n

Taking log of both sides

       log 10.5 = nlog 3.225

        1.0212 = n(0.5085)

         n  =   \frac{1.0212}{(0.5085)}

         n  =  2 \ years

     

4 0
3 years ago
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