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babunello [35]
3 years ago
9

A class of 20 students is visiting the fair today. Each student is 16 years old or younger and will participate in

Mathematics
2 answers:
Finger [1]3 years ago
8 0

Answer:

C.) The Hay Bale Toss would be more skewed.

Step-by-step explanation:

mr Goodwill [35]3 years ago
5 0

Answer:

The interval of 0-19 will increase by 20 of either Hay Bale Toss or Pie Eating Contest.

Step-by-step explanation:

Number of students visiting the fair = 20

Age group = 0-16

In the histogram, this age group falls in the first interval which is 0-19.

  • If all 20 students joined the Hay Bale Toss then the bar of 0-19 of Hay Bale Toss will increase from 40 to 60 and the graph of Pie Eating Contest will remain the same.
  • If all 20 students joined the Pie Eating Contest then the bar of 0-19 of Hay Bale Toss will increase from 20 to 40 and the graph of Hay Bale Toss will remain the same.

<em>Therefore, only one if the graph's interval of 0-19 will increase by 20 whereas the other graph would remain the same.</em>

!!

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A rhombus ABCD has AB = 10 and m∠A = 60°. Find the lengths of the diagonals of ABCD.
melisa1 [442]
Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus

First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°. 

Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.

For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.

\overline{OB}:\overline{AB} = 1:2
\overline {OB}:10 = 1:2
\overline{OB} = \frac{1}{2}(10) = 5

Similarly, we have

\overline{AO}:\overline{AB} = \sqrt{3}:2
\overline {AO}:10 = \sqrt{3}:2
\overline{AO} = \frac{\sqrt{3}}{2}(10) = 5\sqrt{3}

Now, to find the lengths of the diagonals, 

\overline{AD} = 2(\overline{AO}) = 10\sqrt{3}
\overline{BC} = 2(\overline{OB}) = 10

So, the lengths of the diagonals are 10 and 10√3.

Answer: 10 and 10√3 units

8 0
3 years ago
What is e-1/2f when e=15 and f=2
dusya [7]

Answer:

14

Step-by-step explanation:

Replace with the values

15-1/2(2) = 15-1 = 14

3 0
3 years ago
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What does pq equal and how do I find it???
Kay [80]
Use trigonometry.

sinQ = 14/50 = 0.28
-> angle Q = sin^-1(0.28) = approx 16 degrees

-> cosQ = A/H -> cos16 = PQ/50

=> PQ = 50*cos16 = approx 48.06

So yea.
3 0
3 years ago
If anyone knows how to do this please help, its for a test and I have to finish the course by 11:59 tonight
abruzzese [7]
The correct answer would be c. hope this helps
3 0
3 years ago
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Help,??????????????????
abruzzese [7]
So you would find out what number in the 9 times tables goes into 25 and there's your answer x
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