Three important properties of the diagonals of a rhombus that we need for this problem are:
1. the diagonals of a rhombus bisect each other
2. the diagonals form two perpendicular lines
3. the diagonals bisect the angles of the rhombus
First, we can let O be the point where the two diagonals intersect (as shown in the attached image). Using the properties listed above, we can conclude that ∠AOB is equal to 90° and ∠BAO = 60/2 = 30°.
Since a triangle's interior angles have a sum of 180°, then we have ∠ABO = 180 - 90 - 30 = 60°. This shows that the ΔAOB is a 30-60-90 triangle.
For a 30-60-90 triangle, the ratio of the sides facing the corresponding anges is 1:√3:2. So, since we know that AB = 10, we can compute for the rest of the sides.



Similarly, we have



Now, to find the lengths of the diagonals,


So, the lengths of the diagonals are 10 and 10√3.
Answer: 10 and 10√3 units
Answer:
14
Step-by-step explanation:
Replace with the values
15-1/2(2) = 15-1 = 14
Use trigonometry.
sinQ = 14/50 = 0.28
-> angle Q = sin^-1(0.28) = approx 16 degrees
-> cosQ = A/H -> cos16 = PQ/50
=> PQ = 50*cos16 = approx 48.06
So yea.
The correct answer would be c. hope this helps
So you would find out what number in the 9 times tables goes into 25 and there's your answer x