Given:ABCD is a rhombus.
To prove:DE congruent to BE.
In rombus, we know opposite angle are equal.
so, angle DCB = angle BAD
SINCE, ANGLE DCB= BAD
SO, In triangle DCA
angle DCA=angle DAC
similarly, In triangle ABC
angle BAC=angle BCA
since angle BCD=angle BAD
Therefore, angle DAC =angle CAB
so, opposite sides of equal angle are always equal.
so,sides DC=BC
Now, In triangle DEC and in triangle BEC
1. .DC=BC (from above)............(S)
2ANGLE CED=ANGLE CEB (DC=BC)....(A)
3.CE=CE (common sides)(S)
Therefore,DE is congruent to BE (from S.A.S axiom)
Answer:
the answer is 10,000
Step-by-step explanation:
i don't know
I think you do this
how many numbers times itself to the length of the code.
The first thing you would do is subtract 10 from 70 then multiply that by 4 the answer to the whole q is 240 calories. Good luck!
Answer:
50
Step-by-step explanation:
35 - 12 + 13 + 39 - 25 = 50
