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3 years ago

HELP!!!!! If anyone knows the answer please tell me as soon as possible!! PLEASE!!!!

Mathematics

1 answer:

Anon25 [30]3 years ago

8 0

Trapezoid, plot the points down on a graph

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A certain kind of bacteria multiplies at a rate of 150 percent per hour. When a person’s blood has 45,000,000 of these bacteria,

DIA [1.3K]

Initial number of Bacteria = Ao = 100
Number of Bacteria which make the person ill = A = 45,000,000

Growth rate = r = 150% = 1.50

The equation model for this situation is:

$A= A_{o}(1+r)^{t}$

Using the values in above equation, we can write:

$45000000=100(1+1.5)^{t} \\ \\ 
450000=(2.5)^{t} \\ \\ 
log(450000)=log((2.5)^{t}) \\ \\ 
log(450000)=t*log(2.5) \\ \\ 
t= \frac{log(450000)}{log(2.5)} \\ \\ 
t=14.21$

This means, the person will fall sick after about 14 hours.

8 0

3 years ago

Read 2 more answers

Help me please T^T<br><br> Solve for m.<br> m+1/3<-2 1/4

tia_tia [17]

Answer:

answer is the second option m<-2 7/12

Step-by-step explanation:

process:

convert -2 1/4 into an improper fraction

m+1/3 < -9/4

m <-9/4 -1/3

calculate the difference

m<-31/12

turn into a mixed fraction

7 0

2 years ago

a relay team of 4 people runs 3 mile. it each person runs the same distance, how many miles does each person run?

Bingel [31]

Each person runs 3/4 miles.

6 0

2 years ago

Let $f(x) = x^2$ and $g(x) = \sqrt{x}$. Find the area bounded by $f(x)$ and $g(x).$

Anna [14]

Answer:

$\large\boxed{1\dfrac{1}{3}\ u^2}$

Step-by-step explanation:

Let's sketch graphs of functions f(x) and g(x) on one coordinate system (attachment).

Let's calculate the common points:

$x^2=\sqrt{x}\qquad\text{square of both sides}\\\\(x^2)^2=\left(\sqrt{x}\right)^2\\\\x^4=x\qquad\text{subtract}\ x\ \text{from both sides}\\\\x^4-x=0\qquad\text{distribute}\\\\x(x^3-1)=0\iff x=0\ \vee\ x^3-1=0\\\\x^3-1=0\qquad\text{add 1 to both sides}\\\\x^3=1\to x=\sqrt[3]1\to x=1$

The area to be calculated is the area in the interval [0, 1] bounded by the graph g(x) and the axis x minus the area bounded by the graph f(x) and the axis x.

We have integrals:

$\int\limits_{0}^1(\sqrt{x})dx-\int\limits_{0}^1(x^2)dx=(*)\\\\\int(\sqrt{x})dx=\int\left(x^\frac{1}{2}\right)dx=\dfrac{2}{3}x^\frac{3}{2}=\dfrac{2x\sqrt{x}}{3}\\\\\int(x^2)dx=\dfrac{1}{3}x^3\\\\(*)=\left(\dfrac{2x\sqrt{x}}{2}\right]^1_0-\left(\dfrac{1}{3}x^3\right]^1_0=\dfrac{2(1)\sqrt{1}}{2}-\dfrac{2(0)\sqrt{0}}{2}-\left(\dfrac{1}{3}(1)^3-\dfrac{1}{3}(0)^3\right)\\\\=\dfrac{2(1)(1)}{2}-\dfrac{2(0)(0)}{2}-\dfrac{1}{3}(1)}+\dfrac{1}{3}(0)=2-0-\dfrac{1}{3}+0=1\dfrac{1}{3}$

6 0

3 years ago

Help? don't know what to pick, and please dont choose randomly

Yakvenalex [24]

Answer:

yess!!!

step-by-step explained.

......

6 0

3 years ago

Read 2 more answers