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PIT_PIT [208]
3 years ago
14

Compare and contrast expressions equations and inequalities

Mathematics
1 answer:
babymother [125]3 years ago
4 0
Equations can have one solution, but inequalities have infinite solutions.

Hope this helps!
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Find the length of each arc. Round to the nearest tenth.
avanturin [10]

Answer:

arc ≈ 5.5 units

Step-by-step explanation:

The arc of the circle is calculated as

arc = circumference of circle × fraction of circle

     = 2πr × \frac{\frac{\pi }{2} }{2\pi } ( r is the radius )

    = 2π × 3.5 × \frac{1}{4}

    = \frac{7\pi }{4}

    ≈ 5.5 ( to the nearest tenth )

7 0
2 years ago
Math 15
avanturin [10]

Answer:

  • c. 126.27 square feet

Step-by-step explanation:

<u>Area of rhombus is:</u>

  • A = pq/2, where p and q are diagonals

<u>We have:</u>

  • p = 18.3 ft
  • q = 13.8 ft

<u>The area is:</u>

  • A = 18.3*13.8/2 = 126.27 ft²

Correct choice is C

4 0
2 years ago
A square is constructed with an area of 18 square feet. What is the approximate length of one side?
natka813 [3]
Just get a calculator and do 18 divide by 4
7 0
3 years ago
Read 2 more answers
What is a possible value for the missing term of the geometric sequences?
Ganezh [65]
A(n)=ar^(n-1)  and we can find the rate upon using the ratio of two points...

50/1250=1250r^2/1250r^0

1/25=r^2

r=1/5  so

a(n)=1250(1/5)^1=250

...

You could have also found the geometric mean which is actually quite efficient too...

The geometric mean is equal to the product of a set of elements raised to the 1/n the power where n is the number of multiplicands...in this case:

gm=(1250*50)^(1/2)=250
8 0
2 years ago
Read 2 more answers
What is the value for ƒ(x) = 3x^2+1 when x= 1/2<br><br> 3<br> 6<br> 9<br> 15
lisabon 2012 [21]

None of your answers above will answer the question. The proper value for x = 1/2 is 7/4. The work for this is below.


f(x) = 3x^2 + 1

f(1/2) = 3(1/2)^2 + 1

f(1/2) = 3(1/4) + 1

f(1/2) = 3/4 + 1

f(1/2) = 7/4


I assume you may have missed something in typing, but 7/4 would be your answer.

5 0
3 years ago
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