Answer:
Step-by-step explanation:
The given relation between length and width can be used to write an expression for area. The equation setting that equal to the given area can be solved to find the shed dimensions.
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<h3>Given relation</h3>
Let x represent the width of the shed. Then the length is (2x+3), and the area is ...
A = LW
20 = (2x+3)(x) . . . . . area of the shed
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<h3>Solution</h3>
Completing the square gives ...
2x² +3x +1.125 = 21.125 . . . . . . add 2(9/16) to both sides
2(x +0.75)² = 21.125 . . . . . . . write as a square
x +0.75 = √10.5625 . . . . . divide by 2, take the square root
x = -0.75 +3.25 = 2.50 . . . . . subtract 0.75, keep the positive solution
The width of the shed is 2.5 feet; the length is 2(2.5)+3 = 8 feet.
Answer:
n > -4/3
Step by step
Step by step solution :
Step 1 :
Equation at the end of step 1 :
25 - (0 - 3 • (4n - 3)) > 0
Step 2 :
Step 3 :
Pulling out like terms :
3.1 Pull out like factors :
12n + 16 = 4 • (3n + 4)
Equation at the end of step 3 :
4 • (3n + 4) > 0
Step 4 :
4.1 Divide both sides by 4
4.2 Divide both sides by 3
n+(4/3) > 0
Solve Basic Inequality :
4.3 Subtract 4/3 from both sides
n > -4/3
La longitud del arco (s) en una circunferencia, conociendo el radio (r) y el ángulo (θ) que forman los dos radios, es:
s = r∙θ
Con el ángulo en radianes
F V7 w7 :
Answer:
C, 45 degrees
Step-by-step explanation:
Each length is 72 times longer so the actual dimensions are 381.6cm by 576 cm
