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3 years ago

I need it asap!!! Help a struggling geometry student out!!

Mathematics

2 answers:

coldgirl [10]3 years ago

3 0

Answer:

I would say C

Step-by-step explanation:

Elanso [62]3 years ago

3 0

9514 1404 393

Answer:

6. A

7. 80°

8. 20°

Step-by-step explanation:

It is helpful to read the question and identify the particular parts of the diagram it is asking about.

The corresponding hash marks mean the marked segments are congruent. These show you that ΔMQT is isosceles, so angles QMT and QTM are congruent. The sets of hash marks on NT and SM mean those segments are congruent. Of course MT is congruent to itself.

These facts let you conclude that triangles NTM and SMT are congruent by the SAS theorem. (The base angles of ΔMQT are between the pairs of congruent sides.)

The only answer choice referencing SAS is the first one, choice A.

Based on the previous question, it is a simple matter to show ΔMPT ≅ ΔTRM by SAS. Then angles MPT and TRM are congruent. Angle MPT is supplementary to angle MPN, so is 180° -100° = 80°.

Angle TRM is congruent to angle MPT, so is 80°.

With reference to ΔMQN, angle MQT is an external angle. Its measure is equal to the sum of the opposite internal angles QNM and QMN:

∠MQT = ∠NMQ + ∠QNM

95° = 75° + ∠QNM

20° = ∠QNM

From problem 6, we know that angle N is congruent to angle S, so, ...

∠TSR = ∠QNM = 20°

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The amount of time that a customer spends waiting at an airport check-in counter is a random variable with mean 8.0 minutes and

strojnjashka [21]

Answer:

P ( 5 < X < 10 ) = 1

Step-by-step explanation:

Given:-

- Sample size n = 49

- The sample mean u = 8.0 mins

- The sample standard deviation s = 1.3 mins

Find:-

Find the probability that the average time waiting in line for these customers is between 5 and 10 minutes.

Solution:-

- We will assume that the random variable follows a normal distribution with, then its given that the sample also exhibits normality. The population distribution can be expressed as:

X ~ N ( u , s /√n )

Where

s /√n = 1.3 / √49 = 0.2143

- The required probability is P ( 5 < X < 10 ) minutes. The standardized values are:

P ( 5 < X < 10 ) = P ( (5 - 8) / 0.2143 < Z < (10-8) / 0.2143 )

= P ( -14.93 < Z < 8.4 )

- Using standard Z-table we have:

P ( 5 < X < 10 ) = P ( -14.93 < Z < 8.4 ) = 1

7 0

3 years ago

1. The probability of telesales representative making a sale on a customer call is 0.15.

Mumz [18]

Answer:

$n = 33$

$n = 19$

Step-by-step explanation:

From the question we are told that

The probability of telesales representative making a sale on a customer call is $p = 0.15$

The mean is $\mu = 5$

Generally the distribution of sales call made by a telesales representative follows a binomial distribution

i.e

$X \~ \ \ \ B(n , p)$

and the probability distribution function for binomial distribution is

$P(X = x) = ^{n}C_x * p^x * (1- p)^{n-x}$

Here C stands for combination hence we are going to be making use of the combination function in our calculators

Generally the mean is mathematically represented as

$\mu = n* p$

=> $5= n * 0.15$

=> $n = 33$

Generally the least number of calls that need to be made by a representative for the probability of at least 1 sale to exceed 0.95 is mathematically represented as

$P( X \ge 1) = 1 - P( X < 1 ) > 0.95$