Somebody please help

A ball is thrown from an initial height of 3 feet with an initial upward velocity of 37 fts. The ball's height h (in feet) after

tatyana61 [14]

Answer:

t=(37+root89)/32,(37-root89)/32

Step-by-step explanation:

Solve the equation:

23=3+37t-16t^2

5 0

2 years ago

What is the perimeter of the rectangular with a length of 2.5 m and breadth of 1.6m<br><br><br>

lana [24]

Answer:

Step-by-step explanation:

length of the rectangle = 2.5 m

breadth of the rectangle = 1.6 m

Perimeter of rectangle = 2( l + b )

= 2 × 4.1

= 8.2 m

Hope this helps

plz mark as brainliest!!!!!

6 0

3 years ago

Read 2 more answers

Plz help me plz f(89) = -481.4 and f(126) = -677.5

yaroslaw [1]

Answer:do u have the answer

Step-by-step explanation:

4 0

3 years ago

lesya692 [45]

Answer:

x = 1.2

Step-by-step explanation:

AD/AB = DE/BC (Similarity Theorem)

AD = 6 + 4 = 10

AB = 6

DE = 2

BC = x

Plug in the values

10/6 = 2/x

Cross multiply

10*x = 2*6

10x = 12

Divide both sides by 10

x = 12/10

x = 1.2

8 0

3 years ago

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit

coldgirl [10]

Changing the equation into slope form: $y = mx + c$ , where $m$ is the slope [gradient] and $c$ is the y-intercept.

$2x+3y=1470$
$3y = -2x+1470$
$y= - \frac{2}{3}x+ \frac{1470}{3}$
$y=- \frac{2}{3}x+490$

The gradient is $- \frac{2}{3}$ and y-intercept is at $y=490$

Graphing $y=- \frac{2}{3}x+490$ using slope-intercept method:
a) The slope is a negative slope. The line will go 'down hill'
b) The line must pass the point (0, 490)
c) The line will intercept the x-axis at y = 0
   $0 = - \frac{2}{3}x+490$
   $\frac{2}{3}x = 490$
   $2x = 1470$
   $x = \frac{1470}{2}$
   $x = 735$
So, x-intercept is at (735, 0)

The graph of this function is shown below. The intercepts are labelled at:
y = 490
x = 735

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Next month's profit equation

$2x+3y=1593$

Rewriting this into slope-equation form

$3y = -2x+1593$
$y=- \frac{2}{3}+ \frac{1593}{3}$
$y= - \frac{2}{3}+531$

The gradient, $m$ , equals to $- \frac{2}{3}$
The y-intercept, $c$ , equals to 531

The equation still has the same gradient with last month's profit equation but different y-intercept.

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A linear graph show points of (0, 300) and (450, 0)

We work out the slope:
$\frac{300-0}{0-450} = \frac{300}{-450}=- \frac{20}{30} =- \frac{2}{3}$

Y-intercept at x = 0, so it's at y = 300

Equation $y = - \frac{2}{3}+300$

6 0

3 years ago