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madam [21]
3 years ago
9

2.75 As a fraction in simplest form

Mathematics
2 answers:
Igoryamba3 years ago
8 0
2 3/4, because <span>.75 is like 25 50 75 100 75 is third which makes it the third out of the fourth and before the decimal is 2 which is a whole number so that makes it just two and your 3/4 = 2 and 3/4</span>
marshall27 [118]3 years ago
7 0
2.75=2 3/4 because you would say 2.75 as two and seventy-five hundredths. Seventy-five hundredths is just like 3 quarters out of 4 because 1 quarter=25. 2=50. 3=75. So, 2.75 as a fraction in simplest form is 2 3/4.
Hope I helped:D
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The magnitude of the second atom relative to the first = 10⁻¹¹ / 10⁻¹³ = 100

<h3>Equation</h3>

An equation is an expression used to show the relationship between two or more variables or numbers.

The magnitude of the second atom relative to the first = magnitude of second atom / magnitude of first atom

The magnitude of the second atom relative to the first = 10⁻¹¹ / 10⁻¹³ = 100

Find out more on Equation at: brainly.com/question/13763238

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2 years ago
Jace went shopping for a new phone. The listed price of the phone was $50, but the
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Answer:

1.50

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Can someone help me answer these two questions
andrew11 [14]

Answer:

C) 7=y=5x+11

B) m=-4/5, b=13/5

Step-by-step explanation:

<u>Problem 1:</u>

A function is linear if its slope is constant and/or its graph is straight (that means 1-degree polynomials only). Therefore, C is the only correct answer.

<u>Problem 2:</u>

Convert to slope-intercept form (y=mx+b):

4x+5y=13

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y=13/5-4/5x

y=-4/5x+13/5

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8 0
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Can anyone help with this please
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Answer:the correct answer is b

Step-by-step explanation:

Took the test also download the app called photo math all I have to do is take the photo of the problem it’s free of charge

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3 years ago
Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean
LuckyWell [14K]

Answer:

t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240

df = n_1 +n_2 -2 = 10+15-2= 23

p_v = 2*P(t_{23} >2.240) = 0.035

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

Step-by-step explanation:

Data given

\bar X_1 = 1085 sample mean for group 1

\bar X_2 = 1034 sample mean for group 2

n_1 = 10 sample size for group 1

n_2 = 15 sample size for group 2

s_1 = 52 sample deviation for group 1

s_2 = 61 sample deviation for group 2

Solution

We want to check if the two means are equal so then the system of hypothesis are:

Null hypothesis: \mu_1= \mu_2

Alternative hypothesis: \mu_1 \neq \mu_2

And the statistic is given by:

t = \frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}

And replacing we got:

t = \frac{1085-1034}{\sqrt{\frac{52^2}{10} +\frac{61^2}{15}}} = 2.240

The degrees of freedom are given by:

df = n_1 +n_2 -2 = 10+15-2= 23

And the p value would be:

p_v = 2*P(t_{23} >2.240) = 0.035

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

8 0
3 years ago
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