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3 years ago

8

Some one pls help me

1 answer:

andriy [413]3 years ago

6 0

Answer:

Madam Gazelle

Step-by-step explanation:

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A plumber charges a base fee of $55 for service call plus &35 per hour for each hour worked during the service call. Write a

Tasya [4]

Answer:

p = 55 + 35h

Step-by-step explanation:

Let p and h represent the price of the service call and the hours worked, respectively. The price charged is 35 dollars for each hour, so the time-based part of the price is 35h. The base fee of 55 dollars is added to that for a total price of ...

p = 55 + 35h

5 0

3 years ago

50 POINTS FOR THIS

sergejj [24]

Answer:

i have the same problem as you, i need help as well

Step-by-step explanation:

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3 years ago

The graph of f ′ (x), the derivative of f of x, is continuous for all x and consists of five line segments as shown below. Given

Rom4ik [11]

$f'(x)\ge0$ for all $x$ in [-3, 0], so $f(x)$ is non-decreasing over this interval, and in particular we know right away that its minimum value must occur at $x=-3$ .

From the plot, it's clear that on [-3, 0] we have $f'(x)=-x$ . So

$f(x)=\displaystyle\int(-x)\,\mathrm dx=-\dfrac{x^2}2+C$

for some constant $C$ . Given that $f(0)=7$ , we find that

$7=-\dfrac{0^2}2+C\implies C=7$

so that on [-3, 0] we have

$f(x)=-\dfrac{x^2}2+7$

and

$f(-3)=\dfrac52=2.5$

5 0

4 years ago

Jesse recorded the temperatures at which two oils freeze: Oil Temperature Sesame oil −6.2 °C Peanut oil 3.1 °C Which statement a

olga nikolaevna [1]

Answer:

Step-by-step explanation:

Where are the statements?

8 0

3 years ago

Read 2 more answers

La probabilidad de que el estudiante A apruebe un examen de MM-100 es 0.6, la probabilidad de que apruebe un estudiante B es 0.4

ivanzaharov [21]

Answer:

0.5 = 50% probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.

Step-by-step explanation:

La probabilidad condicional :

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

En el cual:

P(B|A) es la probabilidad de que ocurra el evento B, dado que A sucedió.

$P(A \cap B)$ es la probabilidad de que ocurran tanto A como B.

P(A) es la probabilidad de que ocurra A.

En esta pregunta :

Evento A: Estudiante A aprueba.

Evento B: Estudiante B aprueba.

La probabilidad de que el estudiante A apruebe un examen de MM-100 es 0.6

Entonces $P(A) = 0.6$

La probabilidad de que ambos estudiantes aprueben es 0.3

Entonces $P(A \cap B) = 0.3$

¿Cual es la probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.?

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3}{0.6} = 0.5$

0.5 = 50% probabilidad de que apruebe el estudiante B dado que el estudiante A aprueba.

6 0

3 years ago