P = 2(L + W)
P = 28
L = 2W - 1
28 = 2(2W - 1 + W)
28 = 2(3W - 1)
28 = 6W - 2
28 + 2 = 6W
30 = 6W
30/6 = W
5 = W ....width is 5 ft
L = 2W - 1
L = 2(5) - 1
L = 10 - 1
L = 9 <=== length is 9 ft
For this case we have the following expression:
(xy ^ -6) / (x ^ -4y ^ 2)
By power properties we can rewrite the expression as:
(x * x ^ 4) / (y ^ 6 * y ^ 2)
Then, for power properties:
Same exponents are added:
(x ^ (4 + 1)) / (y ^ (6 + 2))
(x ^ 5) / (y ^ 8)
Answer:
An expression after the negative exponents have been eliminated is:
(x ^ 5) / (y ^ 8)
To find the probability of landing on a triangle, you will want find the combined areas of the triangles and the total area of the square target.
Divide the area of the combined areas and the total area to find the probability of landing on a triangle.
A = 1/2bh
1/2 x 8 x 8
A = 32 square inches
32 x 4
128 square inches (areas of triangles)
A = bh
26 x 26
A = 676 square inches
128/676 = 0.189
There is an approximate probability of 0.19 of hitting a triangle.
Is this <ABD?
if so, all lines tangent to a circle, its point of tangency is perpendicular to the center of the circle. So <ABD = 90 degrees
I think it's c but I'm not sure to me I think the answer is c
