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3 years ago

How much longer is 3 meters than 3 yards?

Mathematics

1 answer:

mojhsa [17]3 years ago

5 0

3 meters is 9.84252 feet, and 3 yards is 9 feet
So 3 meters is .84252 feet more that 3 yards.

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Suppose the scores on an exam are normally distributed with a mean μ = 75 points, and standard deviation σ = 8 points. Suppose t

alexandr402 [8]

Answer:

89.008

Step-by-step explanation:

z = (x– mean)/ standard deviation

x = z * standard deviation + mean

Now, z value for the top 4% of the exams (which is the same as getting a score below the 96%) has to be found using a z table.

In this case z = 1.751

x = 1.751 * 8 + 75

x = 89.008

6 0

3 years ago

What is the equivalent fraction for 3/7 and blank/21 ??

emmainna [20.7K]

Equivalent for 3/7
7* 3 = 21 then 3* 3 = 9
so 3/7 = 9/21

5 0

4 years ago

A 2-column table with 6 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2. The second

tatiyna

The answer is the first option which is A

3 0

3 years ago

Read 2 more answers

In triangle UVW, the measure of angle W is 90 degrees, UV is 4.7 feet, and WU is 2.2feet. Find the measure of angle u to the nea

Nataly [62]

Answer:62

Step-by-step explanation:

3 0

3 years ago

A: {71,73,79,83,87} B:{57,59,61,67}

Jobisdone [24]

Answer:

$\frac{3}{5}$ .

Step-by-step explanation:

We have been given two sets as A: {71,73,79,83,87} B:{57,59,61,67}. We are asked to find the probability that both numbers are prime, if one number is selected at random from set A, and one number is selected at random from set B.

We can see that in set A, there is only one non-prime number that is 87 as it is divisible by 3.

So there are 4 prime number in set A and total numbers are 5.

$P(\text{Prime number from A})=\frac{4}{5}$

We can see that in set B, there is only one non-prime number that is 57 as it is divisible by 3.

So there are 3 prime number in set B and total numbers are 4.

$P(\text{Prime number from B})=\frac{3}{4}$

Now, we will multiply both probabilities to find the probability that both numbers are prime. We are multiplying probabilities because both events are independent.

$P(\text{Prime number from A and B})=\frac{4}{5}\times \frac{3}{4}$

$P(\text{Prime number from A and B})=\frac{1}{5}\times \frac{3}{1}$

$P(\text{Prime number from A and B})=\frac{3}{5}$

Therefore, the probability that both numbers are prime would be $\frac{3}{5}$ .

4 0

3 years ago