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3 years ago

Point A is at (-7, -7) and point B is at (-6, -1). What is the midpoint

Mathematics

1 answer:

hammer [34]3 years ago

7 0

Answer: Midpoint= -13/2, -4

Step-by-step explanation:

Midpoint formula is (X1+X2)/2, (Y1+Y2)/2

So.

1. (-7+(-6))/2, (-7+(-1))/2

2. That equals -13/2,-4

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3 years ago

Read 2 more answers

Mack wrote the equation x² + 7x + 84 = x² + 13x + 30 to show that the area of a changed rectangle is 84 ft² greater than the are

Sliva [168]

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3 years ago

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On Friday Merinda uses 1/4 of the box of pancake mix to make pancakes. On Saturday she uses 1 1/2 times as much pancake mix as F

Mashutka [201]

Answer:

3/8 of the box

Step-by-step explanation:

On Friday Merinda uses 1/4 of the box of pancake mix to make pancakes.

On Saturday she uses 1 1/2 times as much pancake mix as Friday.

On Friday = 1/4 of the box

On Saturday = 1 1/2 × pancake mix as Friday

$\dfrac{3}{2}\times \dfrac{1}{4}\\\\=\dfrac{3}{8}$

Hence, 3/8 of the box of pancake mix does Merinda use on Saturday.

4 0

3 years ago

After one hour, the hare had finished 2/3 of a 100-yard race. In that same time, the tortoise had finished 42 3/4 yards. How muc

andriy [413]

Answer:

23 11/12 yards or 23.9166 yards

Step-by-step explanation:

2/3 of 100 yard race is equivalent to 66 2/3 yards. Tge difference between the above and 42 3/4 yards covered by tortoise will be

66 2/3- 42 3/4= 23 11/12 yards or 23.91666 yards

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3 years ago

The number of E.coli bacteria cells in a pond of stagnant water can be represented by the function below, where A represents the

liq [111]

Answer:

<u>Option B. 59%</u>

Explanation:

The function that represents the number of E.coli bacteria cells per 100 mL of water as the time t years elapses is:

$A(t)=136(1.123)^{4t}$

The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function:

$rate=(1.123)^{4t}=(1.123)^4=1.590$

Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.

8 0

3 years ago