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3 years ago

If you are doing distance do you add or subtract?

Mathematics

1 answer:

zavuch27 [327]3 years ago

7 0

Answer:

it depends on what the question asks

Step-by-step explanation:

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Nora made 15 gallons of lemonade for a community picnic.

gogolik [260]

Answer:

I also belive for Part A the second one is the answer because it equals 120 Part B is 120 pints! Good Luck! And I hope this Helps!

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3 years ago

Moises is determining the solution to the system of equations that is show below. Equation representing line A: y = one-third x

FrozenT [24]

Answer:

the answer is B

Step-by-step explanation:

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3 years ago

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Can u pls help me with this question asap

RideAnS [48]

Answer:

Step-by-step explanation:

Basically 90 precent of 100 is 90

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3 years ago

The position equation for a particle is s of t equals the square root of the quantity t cubed plus 1 where s is measured in feet

vladimir1956 [14]

$\bf s(t)=\sqrt{t^3+1}
\\\\\\
\cfrac{ds}{dt}=\cfrac{1}{2}(t^3+1)^{-\frac{1}{2}}\cdot 3t^2\implies \boxed{\cfrac{ds}{dt}=\cfrac{3t^2}{2\sqrt{t^3+1}}}\leftarrow v(t)
\\\\\\
\cfrac{d^2s}{dt^2}=\cfrac{6t(2\sqrt{t^3+1})-3t^2\left( \frac{3t^2}{\sqrt{t^3+1}} \right)}{(2\sqrt{t^3+1})^2}\implies 
\cfrac{d^2s}{dt^2}=\cfrac{ \frac{6t(2\sqrt{t^3+1})-1}{\sqrt{t^3+1}} }{4(t^3+1)}$

$\bf \cfrac{d^2s}{dt^2}=\cfrac{6t[2(t^3+1)]-1}{4(t^3+1)\sqrt{t^3+1}}\implies 
\boxed{\cfrac{d^2s}{dt^2}=\cfrac{12t^4+12t-1}{4t^3+4\sqrt{t^3+1}}}\leftarrow a(t)\\\\
-------------------------------\\\\a(2)=\cfrac{215~ft^2}{44~sec}$

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3 years ago

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A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 220 feet of f

MrRa [10]

Answer:

6050 square feet

Step-by-step explanation:

Based on the diagram attached, the area which the available fencing can enclose will measure X x Y feet. As the total length of fencing available is 220 feet, the fenced perimeter must equal 220 feet

$Y + 2X = 220$

$Y = 220 - 2X$

Area of a rectangle is determined by multiplying the length of perpendicular sides:

$Area = X*Y$

$Area = X(220 - 2X)$

$Area = 220X - 2X^{2}$

The derivative of an equation determines the slope at any given point of that equation. At the maximum or minimum point of the equation, the slope will be zero. Therefore, differentiating the equation for area and equating it to zero will give the value of X where the area is maximum.

A simple variable can be differentiated using below concept:

$f(a) = a^{b}$