Cone. Come on bruh how old are u
Would assume:
f(n + 1) = f(n) - 2
f(2) = f(1 + 1) = f(1) - 2 = 18 - 2 = 16
<span>f(3) = f(2 + 1) = f(2) - 2 = 16 - 2 = 14
</span>
<span>f(4) = f(3 + 1) = f(3) - 2 = 14 - 2 = 12
</span>
<span>f(5) = f(4 + 1) = f(4) - 2 = 12 - 2 = 10
</span>
f(5) = 10
0.0757142857142857
I wasnt sure if you wanted me to round to a percific place
Answer:
E(w) = 1600000
v(w) = 240000
Step-by-step explanation:
given data
sequence = 1 million iid (+1 and +2)
probability of transmitting a +1 = 0.4
solution
sequence will be here as
P{Xi = k } = 0.4 for k = +1
0.6 for k = +2
and define is
x1 + x2 + ................ + X1000000
so for expected value for W
E(w) = E( x1 + x2 + ................ + X1000000 ) ......................1
as per the linear probability of expectation
E(w) = 1000000 ( 0.4 × 1 + 0.6 × 2)
E(w) = 1600000
and
for variance of W
v(w) = V ( x1 + x2 + ................ + X1000000 ) ..........................2
v(w) = V x1 + V x2 + ................ + V X1000000
here also same as that xi are i.e d so cov(xi, xj ) = 0 and i ≠ j
so
v(w) = 1000000 ( v(x) )
v(w) = 1000000 ( 0.24)
v(w) = 240000
