WHAT MAKES ELECTRONS JUMP TO OTHER ORBITS AROUND THE NUCLEUS THEN FALL AGAIN

Chemistry

1 answer:

kolezko [41]3 years ago

7 0

Answer:

Explanation:

Electrons absorb energy in photons. This makes the eclectron excited. An electron in an excited state can release energy and fall to a lower orbit

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PLEASE ANSWER NEED HELP!!!!!!!! PLEASE THE CORRECT ANSWER!!!!!!

Norma-Jean [14]

The correct answer is d!!

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3 years ago

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The speed of sound in water is 350m/s. If a sound wave has the frequency of 50Hz.

Elena-2011 [213]

Answer:

Explanation

Let, Wavelength = W,

Given, frequency (f) = 50 Hz, wave velocity (V) = 342 m/s

We know, V = f × W

=> 342 = 50 × W

=> W = 342/50 metre

=> W = 6.84 metre

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3 years ago

Write each element and elements of atoms of the compound Na2PO3F

Rudik [331]

The subscripts tell you <em>how many atoms</em> of an element are in one formula unit of a compound.

If there is no subscript, there is only one atom of the element.

In one formula unit of Na₂PO₃F, there are

Two atoms of sodium (Na)

One atom of phosphorus (P)

Three atoms of oxygen (O)

One atom of fluorine (F)

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3 years ago

A sample of potassium phosphate octahydrate (K3PO4•8H2O) is heated until 7.93 grams of water are released. How many grams did th

Gekata [30.6K]

The original sample of potassium phosphate octahydrate had a mass of 19.6 grams. When it was heated, it released 7.93 grams of water.

Further Explanation:

For every mole of the compound potassium phosphate octahydrate, there are 8 moles of water of hydration which can be removed from the crystal by heating without altering the chemical composition of the substance.

To determine how much original sample was used, the amount of water released upon heating may be used as well as the mole ratio of the water of hydration with the compound itself following the steps below:

Convert mass of water released to moles.
Use the mole ratio of water of hydration to the compound (8 mol water for every mol of potassium phosphate octahydrate) to get the moles of original sample.
Convert the moles of original sample to grams.

STEP 1: Convert 7.93 g water to moles.

$moles \ of\ H_{2}O \ = 7.93 \ g \ H_{2}O \ (\frac{1 \ mol \ H_{2}O}{18.00 \ g \ H_{2}O})\\\boxed {moles \ of \ H_{2}O \ = 0.4406 \ mol}$

STEP 2: Calculate the moles of original sample using the mole ratio: 1 mol K3PO4 8H2O : 8 mol H2O.

$moles \ of \ K_{3}PO_{4}\ 8H_{2}O \ = 0.4406 \ mol \ H_{2}O \ (\frac{1 \ mol \ K_{3}PO_{4}\ 8H_{2}O \ }{8 \ mol \ H_{2}O})\\\\\boxed {moles \ of \ K_{3}PO_{4}\ 8H_{2}O \ = 0.0551 \ mol}$

STEP 3: Convert the moles of original sample to mass.

$mass \ of \ K_{3}PO_{4}\ 8H_{2}O = 0.0551 \ mol \ K_{3}PO_{4}\ 8H_{2}O \ (\frac{356.3885 \ g}{1 \ mol\ K_{3}PO_{4}\ 8H_{2}O})\\ mass \ of \ K_{3}PO_{4}\ 8H_{2}O \ = 19.637 \ g$