3 years ago

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Chemistry

1 answer:

Lena [83]3 years ago

6 0

Answer:

Explanation:

1+1=2

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The boiling point of CH3OCH3 would be________ the boiling point of CH3CH2OH.

PolarNik [594]

The ans is c

Hope it’s help

7 0

3 years ago

Read 2 more answers

Kingsley then adds 44.12 mL of NaOH to 250.00 mL of the HCOOH solution. The neutralization reaction resulted in 0.091 moles of H

Fantom [35]

Answer:

pH = 3.34

Explanation:

We can calculate the pH using Henderson-Hasselbach's equation:

pH = pKa + log $\frac{[HCOO^-]}{[HCOOH]}$

for HCOOH, pKa = 3.75.

We can calculate [HCOO⁻] and [HCOOH] using the given number of moles for each one and the final volume:

Final Volume = 44.12 mL + 250 mL = 294 mL

294 mL / 1000 = 0.294 L

[HCOO⁻] = 0.036 mol / 0.294 L = 0.122 M

[HCOOH] = 0.091 mol / 0.294 L = 0.310 M

Then we proceed to calculate the pH:

pH = 3.75 + log $\frac{0.122}{0.310}$

pH = 3.34

3 0

3 years ago

Determine the Mass Number of the Following Elements:

Phantasy [73]

Answer:

Al 28

B 11

C 14

Sc 46

Na 24

Explanation:

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3 years ago

Electrochemistry - Equilibrium

Ipatiy [6.2K]

Answer:

Explanation:

The relation between equilibrium constant and Ecell is given below .

E⁰cell = (RT / nF ) lnK , F is faraday constant T is 273 + 25 = 298 K

E⁰cell = 1.46 - 1.21 = .25 V

n = 2

Putting the values

.25 = (8.314 x 298 lnK) / (2 x 96485 )

lnK = 19.47

K = 2.85 x 10⁸

2 )

Change in free energy Δ G

Δ G ⁰ = nE⁰ F

n = 4

E⁰ = .4 + .83 = 1.23 V

Δ G ⁰= 4 x 1.23 x 96485

= 474706 J / mol

3 )

E⁰cell = (RT / nF ) lnK

n = 2

1.78 = 8.314 x 298 lnK / 2 x 96485

lnK = 138.638

K = 1.62 x 10⁶⁰

8 0

3 years ago

Student A pushed on the cart with a force of 500 N. Student B pushed on the other side of the cart. The cart did not move. How m

Nadusha1986 [10]

I depends on the height of the other side of the cart. If it was lower, 400 N. If Higher, at least 600 N.

5 0

4 years ago