Potential energy or kinetic energy.
We assume that this gas is an ideal gas. We use the ideal gas equation to calculate the amount of the gas in moles. It is expressed as:
PV = nRT
(672) (1/760) (36.52) = n (0.08206) ( 68 +273.15)
n = 1.15 mol of gas
Hope this answers the question. Have a nice day.
Answer:
The answer to your question is 1.83 x 10²⁵ particles
Explanation:
Data
particles of H₂O = ?
mass of H₂O = 546 g
Process
1.- Calculate the molar mass of Water
Molar mass = (2 x 1) + (1 x 16)
= 2 + 16
= 18 g
2.- Use proportions to find the number of particles. Use Avogadro's number.
18 g ---------------- 6.023 x 10²³ particles
546 g --------------- x
x = (546 x 6.023 x 10²³) / 18
3.- Simplification
x = 3.289 x 10²⁶ / 18
4.- Result
x = 1.83 x 10²⁵ particles
d. Fe(s) and Al(s)
<h3>Further explanation</h3>
In the redox reaction, it is also known
Reducing agents are substances that experience oxidation
Oxidizing agents are substances that experience reduction
The metal activity series is expressed in voltaic series
<em>Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au </em>
The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent
The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent
So that the metal located on the left can push the metal on the right in the redox reaction
The electrodes which are easier to reduce than hydrogen (H), have E cells = +
The electrodes which are easier to oxidize than hydrogen have a sign E cell = -
So the above metals or metal ions will reduce Pb²⁺ (aq) will be located to the left of the Pb in the voltaic series or which have a more negative E cell value (greater reduction power)
The metal : d. Fe(s) and Al(s)
It posed a contradiction to Quantum Theory
