The atomic mass would not change since the mass of an electron is negligible compared to the mass of protons and neutrons
Answer:
Vapour pressure of benzene over the solution is 253 torr
Explanation:
According to Raoult's law for a mixture of two liquid component A and B-
vapour pressure of a component (A) in solution = 
vapour pressure of a component (B) in solution = 
Where 
are mole fraction of component A and B in solution respectively
are vapour pressure of pure A and pure B respectively
Here mole fraction of benzene in solution is 0.340 and vapour pressure of pure benzene is 745 torr
So, vapour pressure of benzene in solution = 
= 253 torr
Answer:
[Au] = 0.171 M
Explanation:
For this question, we assume the rock is 100 % gold.
First of all, we determine the moles of gold
67.3 g . 1mol/ 196.97g = 0.342 moles
Molar concentration is defined as the moles of solute, contained in 1L of solution.
Our solution volume is 2L.
M = 0.342 mol / 2L = 0.171
Molar concentration, also called molarity of solution is the most typical unit of concentration.
We need to crack molecules in
order for us to get the desired molecule. For example, in the extraction of
crude oil, after entering the fractional distillation, it will give products
base on their molecular structure. The products are gasoline, diesel fuel, jet
fuel, wax, asbestos,kerosene.
Q = mct
-Q= energy in Joules
-m = mass in grams
-c= specific heat capacity in J/g degree C
-t = delta temperature in degrees Celsius
So,
Q = m c t
Q = (7 grams)(0.448J/g C)(750 C - 25 C)
Q = 2273.6 J
Your final answer = 2273.6 Joules
