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motikmotik
3 years ago
14

Need ASAP

Physics
2 answers:
romanna [79]3 years ago
4 0
Hey !
Answer: D
Hoping this helps u
olga2289 [7]3 years ago
3 0
The answer is obviously D, because just becasue

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The segment on the left has diameter 1.6 mm, and each of the segments on the right has diameter 0.4 mm. Assume the blood can be
oksian1 [2.3K]

Answer:

Explanation:

The flow entering the first segment will be the same as the flow exiting the second segment, and in both cases it will be equal to the velocity multiplied by the area of the segment. If Flow_{a} = Flow_{b} and Flow = VxA, then you have:

V_{a} x A_{a} = V_{b} x A_{b} (1)

You can also calculate the transversal area of each segment, because blood vessels are cylinders and you know each segment's diameter. The formula to calculate this is:

A = \pi /4 x d^{2}

Replacing d for each segment you have:

Area_{a} = 2.01 mmArea_{b} = 0.13 mm

Now, replacing these values on (1), you have:

V_{a} x 2.01 mm = V_{b} x 0.13 mm

(V_{a} x 2.01 mm)/0.13 mm = V_{b}

15.4 x V_{a} = V_{b}

This means that velocity in the second segment is 15.4 times the velocity in which blood entered the first segment.

5 0
3 years ago
What happens to heat energy after an object is cooled down lolololol asking for my bff
alisha [4.7K]

Answer:

Heat energy does not cool. Objects cool. Energy is not an object. Now, what happens when an object cools is that it gives off some of its thermal energy by one or more mechanisms: radiation, conduction, or convection. In radiation the energy escaped the object as electromagnetic waves - you see the red hot poker slowly dim as it cools, in conduction the energy is transferred Mechanically by the atoms of the hot object being in physical contact with those of the cool object and in convection the hot material moves to a cooler region where it gives up its heat energy by either radiation or conduction.

7 0
3 years ago
How far apart (in mm) must two point charges of 90.0 nC (typical of static electricity) be to have a force of 5.20 N between the
Ede4ka [16]

Answer:

3.74 mm

Explanation:

From coulomb's law,

F = kqq'/r²............... Equation 1

Where F = force, q and q' = the two charges, r = distance between the two charges, k = proportionality constant.

making r the subject of the equation

r = √(kqq'/F)...................... Equation 2

Given: q = q' = 90 nC = 90×10⁻⁹ C,  F = 5.20 N, k = 9.0×10⁹ Nm²/C²

Substitute into equation 2,

r = √(90×10⁻⁹ )².√(9.0×10⁹/5.2)

r = 90×10⁻⁹.√(17.31×10⁸)

r = (90×10⁻⁹)(4.16×10⁴)

r = 374.4×10⁻⁵ m

r = 3.74 mm

Hence the distance between the charge = 3.74 mm

3 0
3 years ago
A model rocket is fired vertically upward from rest. Its acceleration for the first three seconds is a(t) = 60t at which time th
xz_007 [3.2K]

Answer:

(a) 8.4375 s

(b) 1409.06 ft

(c) 40.55 seconds

Explanation:

v’(t)=a(t)=60t therefore

v(t)=\int 60t=60\frac {t^{2}}{2}=30t^{2}

s(t)=\int v=\int 30t^{2}=30\frac {t^{3}}{3}=10t^{3}

For first three seconds

S(3)=10*3^{3}=270

Since motion is vertical and we take upward direction as positive, acceleration is negative hence

a(t)=-32 and v(t)=\int -32=-32t+c but since at t=0 then v=270 hence c=270

-32.2t+270=0 hence

t=270/32=8.4375 s

(b)

s(t)=-16t^{2}+270t+B and since s(0)=270 then

s(t)=-16t^{2}+270t+270

s(8.4375)=-16(8.4375)^{2}+270(8.4375)+270\approx 1409.06 ft

(c)

v(15)=-32(14)+270=-178 ft/s

s(14)=-16(14)^{2}+270(14)+270=914 ft

Average speed in the next 5 seconds becomes \frac {-178-18}{2}=-98 ft/s and s(5)=98(5)=490 ft

The altitude is 914-490=424 ft

Time=\frac {424}{18}=23.6 seconds

Time when rocket hits ground

Total time=3+14+23.6=40.55 seconds

5 0
3 years ago
What happens to an object when an unbalanced force acts on it?
posledela
<span>An object will continue to travel at a constant speed unless acted on by an unbalanced force, and for every force acted on there is an equal and opposite reaction in the other way. So, the speed and direction of the object will be changed.</span>
4 0
4 years ago
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