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3 years ago

It 5/2 not -5/2 and sorry for telling u the

Mathematics

2 answers:

Ber [7]3 years ago

6 0

I don’t really know what you are tying to say sorry

babunello [35]3 years ago

4 0

What does this mean buddy?

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What is equivalent to 5 to the 2nd power times 5 to the 2nd power

adelina 88 [10]

<em>5 to the 2nd power times 5 to the 2nd power is equivalent to 625</em>

<h2>Explanation:</h2>

In this case, we have the following statement:

<em>5 to the 2nd power times 5 to the 2nd power. </em>In a mathematical language:

$5^2\times 5^2$

From product rules, we know that:

$a^n \cdot a^m=a^{n+m}$

Applying this rule to our problem:

$5^2\times 5^2=5^{2+2}=5^4=625$

<em>5 to the 2nd power times 5 to the 2nd power is equivalent to 625</em>

<h2>Learn more:</h2>

Rules of exponents: brainly.com/question/12140557

#LearnWithBrainly

3 0

3 years ago

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Please solve and receive brain list

viktelen [127]

Answer:

verdadero

Step-by-step explanation:

5 0

3 years ago

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Evaluate (-2)^-8 times (-2)^8

fomenos

-2^-8 * -2^8
would simply be 1.
Hope this helps. Don't forget to brianliest!. :)

7 0

3 years ago

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For 10 points, Which of the following containers is the most likely to have a capacity of 38 L?

Katena32 [7]

Answer: water tower because it's a tower

6 0

4 years ago

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In a lab experiment, 80 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to doub

Effectus [21]

Answer:

The hourly growth rate is of 4.43%.

The function showing the number of bacteria after t hours is $P(t) = 80(1.0443)^t$

Step-by-step explanation:

Equation of population growth:

The equation for the population after t hours is given by:

$P(t) = P(0)(1+r)^t$

In which P(0) is the initial population and r is the growth rate, as a decimal.

The conditions are such that the number of bacteria is able to double every 16 hours.

This means that $P(16) = 2P(0)$ . We use this to find r.

$P(t) = P(0)(1+r)^t$

$2P(0) = P(0)(1+r)^{16}$

$(1+r)^{16} = 2$

$\sqrt[16]{(1+r)^{16}} = \sqrt[16]{2}$

$1 + r = 2^{\frac{1}{16}}$

$1 + r = 1.0443$

$r = 1.0443 - 1$

$r = 0.0443$

The hourly growth rate is of 4.43%.

80 bacteria are placed in a petri dish.

This means that $P(0) = 80$ .

$P(t) = P(0)(1+r)^t$

$P(t) = 80(1+0.0443)^t$

$P(t) = 80(1.0443)^t$

The function showing the number of bacteria after t hours is $P(t) = 80(1.0443)^t$

6 0

3 years ago