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3 years ago

given the height and the circumference of the base of a cylinder describe how to find the surface area of the entire cylinder

1 answer:

7 0

The radius of the cylinder is related to its circumference by
.. C = 2πr
.. r = C/(2π)
The area of the cylinder base is given by
.. A = π*r^2 = π*(C/(2π))^2 = C^2/(4π)

The lateral area of the cylinder is given by
.. S = C*h

The total area of the cylinder is the lateral area plus the area of both bases.
.. total area = C*h +2*C^2/(4π)
.. total area = C*h +C^2/(2π) . . . . . . . . area from circumference and height

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Functions<br> F(1) if f(x)=x+3

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Answer:

the ewser is 4

Step-by-step explanation:

sence x=1 1+3 =4

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3 years ago

Divide el rufini6x-4x+2 entre x-2<br> x+2x+x+2 entrex+2

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Step-by-step explanation:

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3 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

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3 years ago

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vampirchik [111]

Answer:

$19.58+$5.00 = $24.58

Step-by-step explanation:

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3 years ago

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What is the sum of the measures of the exterior angles of a decagon?

My name is Ann [436]

Answer:

360°

Step-by-step explanation:

The sum of the exterior angles of any polygon is 360°

sum of exterior angles of decagon = 360°

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2 years ago