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2 years ago

-2x-y=-5 In slope intercept form please! :)

Mathematics

1 answer:

schepotkina [342]2 years ago

8 0

Answer:

-2x - y = -5 in slop intercept form would be y = -2x + 5

Step-by-step explanation:

-2x - y = -5

first add -2x to the left side to move it to the right side because whatever you do to one side u do to the other.

-y = -5 + 2x

divide by -1 on the whole equation

y = -2x + 5 is your answer.

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If G is a 3 x 4 matrix and His a 4x 3 matrix, what is the dimension of GH?

Neko [114]

Answer:

3x3

Step-by-step explanation:

G is a 3 x 4 matrix and His a 4x 3 matrix

In multiplication of matrix a particular formula is used

If G = MN and H = NM then GH = MM

So G= 3x4 and H = 4x3

Then GH = 3x3

The above rule is a rule that binds matrix multiplication and allows for an easier calculations and also helps check the possibility of the multiplication.

As for the above, the multiplication is possible an the result of the multiplication will give us a 3x3 matrix

6 0

2 years ago

Multiply 1/8 x 3/4 =

Novay_Z [31]

Answer:

3/32

Step-by-step explanation:

1 times 3= 3 and 8 times 4=32

8 0

3 years ago

Read 2 more answers

PlsHurry Blanck Is 7 times as much as 4

erma4kov [3.2K]

Answer:

Step-by-step explanation:

7 x 4 = 28

hopefully this helps you :)

pls mark brainlest ;)

3 0

2 years ago

Solve 5x^2 − 3x + 17 = 9.

Vedmedyk [2.9K]

Answer:

The roots of the equation are x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

⇒ 5x² − 3x + 17 - 9 = 0

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = $\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = $\frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}$

x = $\frac{3\pm\sqrt{9-160}}{10}$

x = $\frac{3+\sqrt{-151}}{10}$ and x = $\frac{3-\sqrt{-151}}{10}$

x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

here i = √(-1)

Hence,

The roots of the equation are x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

and there are no real roots of the equation given above

7 0

2 years ago

Eric's class consists of 12 males and 16 females. If 3 students are selected at random, find the probability that they

Reptile [31]

Answer:

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

Step-by-step explanation:

Let 'M' be the event of selecting males n(M) = 12

Number of ways of choosing 3 students From all males and females

$n(M) = 28C_{3} = \frac{28!}{(28-3)!3!} =\frac{28 X 27 X 26}{3 X 2 X 1 } = 3,276$

Number of ways of choosing 3 students From all males

$n(M) = 12C_{3} = \frac{12!}{(12-3)!3!} =\frac{12 X 11 X 10}{3 X 2 X 1 } =220$

The probability that all are male of choosing '3' students

$P(E) = \frac{n(M)}{n(S)} = \frac{12 C_{3} }{28 C_{3} }$

$P(E) = \frac{12 C_{3} }{28 C_{3} } = \frac{220}{3276}$

P(E) = 0.067 = 6.71%

Final answer:-

The probability that all are male of choosing '3' students

P(E) = 0.067 = 6.71%

3 0

3 years ago