OK. These problems are easy if you know the quadratic formula,
and they're impossible if you don't.
Here's the quadratic formula:
When the equation is in the form of Ax² + Bx + C = 0
then x = [ -B plus or minus √(B²-4AC) ] / 2A
I'm sure that formula is in your text or your study notes,
right before these questions. You should cut it out or
copy it, and tape it inside the cover of your notebook.
Then, you'll always have it when you need it, until
you have it memorized and can rattle it off.
The first question says 3x² + 5x + 2 = 0
Is this in the form of Ax² + Bx + C = 0 ?
Yes ! A=3 B=5 C=2
so you can use the quadratic formula to solve it.
x = [ -B plus or minus √(B²-4AC) ] / 2A
= [ -5 plus or minus √(5² - 4·3·2) ] / 2·3
= [ -5 plus or minus √(25 - 24) ] / 6
= [ -5 plus or minus √1 ] / 6
x = -4 / 6 = -2/3
and
x = -6 / 6 = -1 .
_______________________________________
The second question says
4x² + 5x - 1 = 0
Is this in the form of Ax² + Bx + C = 0 ?
Yes it is ! A=4 B=5 C= -1
so you can use the quadratic formula to solve it.
x = [ -B plus or minus √(B²-4AC) ] / 2A
Now, you take it from here.
Answer:
7 6/18
Step-by-step explanation:
Answer:
<h3>⇒ A. 2 should be distributed as 2y + 12, y = 6</h3>
Step-by-step explanation:
Here are the steps to solve this equation:
<u>Given:</u>
First step: 2(y+6)-4y
Use the distributive property.
<u>Distributive property:</u>
<h3>
⇒ A(B+C)=AB+AC</h3>
2(y+6)
2*y=2y
2*6=12
2y+12
Isolate the term of y from one side of the equations.
2y+12=4y
Subtract by 12 from both sides.
2y+12-12=4y-12
Solve.
2y=4y-12
Then, you subtract by 4y from both sides.
2y-4y=4y-12-4y
Solve.
2y-4y=-2y
-2y=-12
Divide by -2 from both sides.
Solve.
Divide the numbers from left to right.
<u>Solutions:</u>
-12/-2=6
- <u>Therefore, the correct answer is A. "2 should be distributed as 2y+12, y=6".</u>
I hope this helps. Let me know if you have any questions.
Since we have a transverse line that cuts through the straight line parallel to the height, then we can see that the angles are divided into two sections.
We also have vertically opposite angles, since the angle sum of a straight line is 180°. We have perpendicular lines since we are given a 90° angle. Thus, we know the missing angle is 45°.
Thus, 45 + x = 180
x = 135°
