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3 years ago

Greg's soccer team is selling sets of 3 raffle tickets for $5.00. What is the constant of proportionality of dollars per ticket?

Mathematics

2 answers:

stellarik [79]3 years ago

8 0

5, I believe. Hope this was right for you!

vodka [1.7K]3 years ago

6 0

The constant is 5. :)

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Use Wolframalpha to find the exact volume of the solid obtained by rotating about x = [pi]/2 the region bounded by y = sin^2x, y

Alex777 [14]

Answer:

Step-by-step explanation:

Here the region between two curves is rotated about a vertical line.

The functions are

$y = sin^2x, \\y = sin^4x, \\x in [0,[pi]/2].$

Intersecting points are x=0 and x =pi/2

Since rotated about x = pi/2 we get

using cylindrical shell method

Volume = $2\pi rh\\=2\pi \int\limits^\frac{\pi}{2} _0 {xy} \, dx \\=2\pi \int\limits^\frac{\pi}{2} _0 (x+\frac{\pi}{2} )(sin^2 x -sin^4 x) dx\\$

From wolfram alpha we find that

Volume= $2\pi (\frac{3\pi^2 }{64)} =\frac{6\pi^3}{64}$

4 0

3 years ago

The following are the ages (years) of 5 people in a room:

Nata [24]

Answer:

The age of the person who entered the room is 15

Step-by-step explanation:

Ages of 5 people in a room are:

17, 16, 15, 17, 22

A person enters room, the mean age of 6 people is 17.

We need to find the age of person who entered the room.

We know that: $Mean=\frac{Sum\:of\:all\:data\:values}{Number\:of\:data\:Values}$

Now, we have mean of 6 people that is 17

We know the age of 5 people while age of one person is unknown.

Let age of person which is unknown= x

So, we can write:

Sum of all data values = 17+16+ 15+ 17+ 22+x

where x is the age of person who enters the room.

Finding x

$Mean=\frac{Sum\:of\:all\:data\:values}{Number\:of\:data\:Values}\\17=\frac{17+16+ 15+ 17+ 22+x}{6}\\17=\frac{87+x}{6}\\17*6=87+x\\102=87+x\\x=102-87\\x=15$

So, we get the value of x: x=15

Therefore, the age of the person who entered the room is 15.

5 0

3 years ago

Solve the equation by finding the common multiple.

Monica [59]

Answer:

1. 17/24

2. 1 1/8

3. 1 1/6

4. 1 5/24

5. 1. 1/4

6 0

2 years ago

Suppose a family has three children of different ages. We assume that all combinations of boys and girls are equally likely. (a)

Ivan

Answer:

a) There are 8 possible combinations and each probability is 1/8.

b) The probability that it is a boy given that there are two girls is 3/8

Step-by-step explanation:

a) The sample space is given by:

BBB (3 boys)

BBG (Boy, boy, girl)

BGB (Boy, girl, boy)

BGG (Boy, girl, girl)

GBB (girl, boy, boy)

GBG (girl, boy, girl)

GGB (girl, girl, boy)

GGG (3 girls)

The probability of each combination is the same:

P(BBB)=P(B∩B∩B)= $\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{1}{8}$

2) There are three possible combinations in which there are 2 girls and 1 boy:

BGG, GBG, GGB

So the probability is given by:

P(BGG ∪ GBG ∪ GGB)= $\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}+\frac{1}{2} \frac{1}{2} \frac{1}{2}=\frac{3}{8}$

6 0

3 years ago

PLEASE HELP (unknown answers will be deleted)

Shtirlitz [24]

Answer:

where's the assignment

8 0

3 years ago